日期:2014-05-16  浏览次数:20545 次

两表通过中间表多对多关联用HQL查询(重写)

如有user表,role表,userrole表,3者之间的关系是,user表和role表通过userrole表多对多关联。

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user类:
public class user implements java.io.Serializable {
private Integer userId;
private String userName;
private Set userrole= new HashSet(0);
//get和set省略
}

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role类:

public role implements java.io.Serializable {
private Integer roleId;
private String roleName;
private Set userrole= new HashSet(0);
//get和set省略
}

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userrole类:

public userrole implements java.io.Serializable {
private Integer userroleID;
private role role;
private user user;
//get和set省略
}

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对应的xml(只捡关联部分):


user.hbm.xml:
<set name="userrole" inverse="true">
<key>
<column name="userId" not-null="true" />
</key>
<one-to-many class="mo.hibernate.map.userrole" />
</set>

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role.hbm.xml:
<set name="userrole" inverse="true">
<key>
<column name="roleId" not-null="true" />
</key>
<one-to-many class="mo.hibernate.map.userrole" />
</set>


userrole.hbm.xml:
<many-to-one name="role" class="mo.hibernate.map.role" fetch="select">
<column name="roleId" not-null="true" />
</many-to-one>
<many-to-one name="user" class="mo.hibernate.map.user" fetch="select">
<column name="userId" not-null="true" />
</many-to-one>

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问题是:如何用hql查找出角色为admin的用户的id和名字?

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hql:select u.userId,u.userName from user u,userrole ur,role r where u.userID in(ur.user) and r.roleName='admin' and ur.userroleID in elements(r.userrole)

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本例用到了in和in elements关键字,区别在于in elements用于set,in用于类对象。