日期:2014-05-16  浏览次数:20548 次

Oracle行列转换小结

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目录结构如下:

  • 行转列
  • 列转行

[一]、行转列

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1.1、初始测试数据

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表结构:TEST_TB_GRADE

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create table TEST_TB_GRADE
(
  ID        NUMBER(10) not null,
  USER_NAME VARCHAR2(20 CHAR),
  COURSE    VARCHAR2(20 CHAR),
  SCORE     FLOAT
)

?初始数据如下图:


???????????????????????

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1.2、 如果需要实现如下的查询效果图:


????????????????????

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这就是最常见的行转列,主要原理是利用decode函数、聚集函数(sum),结合group by分组实现的,具体的sql如下:

select t.user_name,
  sum(decode(t.course, '语文', score,null)) as CHINESE,
  sum(decode(t.course, '数学', score,null)) as MATH,
  sum(decode(t.course, '英语', score,null)) as ENGLISH
from test_tb_grade t
group by t.user_name
order by t.user_name
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1.3、延伸

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如果要实现对各门功课的不同分数段进行统计,效果图如下:


???????????? ? ?

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具体的实现sql如下:

select t2.SCORE_GP,
  sum(decode(t2.course, '语文', COUNTNUM,null)) as CHINESE,
  sum(decode(t2.course, '数学', COUNTNUM,null)) as MATH,
  sum(decode(t2.course, '英语', COUNTNUM,null)) as ENGLISH
from (
  select t.course,
         case when t.score  <60 then '00-60'
              when t.score >=60 and t.score <80  then '60-80'
              when t.score >=80 then '80-100' end as SCORE_GP,
         count(t.score) as COUNTNUM
  FROM test_tb_grade t
  group by t.course, 
        case when t.score  <60  then '00-60'
              when t.score >=60 and t.score <80  then '60-80'
              when t.score >=80 then '80-100' end
  order by t.course ) t2
group by t2.SCORE_GP
order by t2.SCORE_GP
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[二]、列转行

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1.1、初始测试数据

??????? 表结构:TEST_TB_GRADE2

create table TEST_TB_GRADE2
(
  ID         NUMBER(10) not null,
  USER_NAME  VARCHAR2(20 CHAR),
  CN_SCORE   FLOAT,
  MATH_SCORE FLOAT,
  EN_SCORE   FLOAT
)
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??????? 初始数据如下图:


???????

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1.2、 如果需要实现如下的查询效果图:


??????????????????????

?

这就是最常见的列转行,主要原理是利用SQL里面的union,具体的sql语句如下:

select user_name, '语文' COURSE , CN_SCORE as SCORE from test_tb_grade2 
union select user_name, '数学' COURSE, MATH_SCORE as SCORE from test_tb_grade2 
union select user_name, '英语' COURSE, EN_SCORE as SCORE from test_tb_grade2 
order by user_name,COURSE 

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?也可以利用【 insert all into ... select 】来实现,首先需要先建一个表TEST_TB_GRADE3:

create table TEST_TB_GRADE3  
    ( 
      USER_NAME VARCHAR2(20 CHAR),  
      COURSE    VARCHAR2(20 CHAR),  
      SCORE     FLOAT  
    )  

?再执行下面的sql:

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insert all
into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '语文', CN_SCORE)
into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '数学', MATH_SCORE)
into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '英语', EN_SCORE)
select user_name, CN_SCORE, MATH_SCORE, EN_SCORE from test_tb_grade2;
commit;

?别忘记commit操作,然后再查询TEST_TB_GRADE3,发现表中的数据就是列转成行了。

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本文连接:http://sjsky.iteye.com/blog/1152167

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