日期:2014-05-16 浏览次数:20481 次
?
解决方法一:加一个exception异常处理
? exception when no_data_found then
??? ....
?
解决方法二:更改select语句,如:
? select count(*) field into var from table where ....
增加一个count(*)即使没有找到数据,也会返回0,而不是null。
?
?
转贴:http://www.itpub.net/thread-821395-1-1.html
?
请问:在执行以下语句时报错。
declare
? ?? ???v_spec? ???varchar2(255);
begin
? ???for r in (select subne.id, subne.subneassetid from subne where subne.subneassetid >0)
? ???loop
? ?? ?? ?? ?select subnetype.subnemodel into v_spec from subnetype , subne
? ?? ?? ?? ?? ?? ? where??subne.id = r.id and subne.subnetypeid = subnetype.id;
? ?? ?? ?? ?update asset set specformula = v_spec where id = r.subneassetid and specformula is null;
? ???end loop;
end;
ORA-01403: 未找到数据
ORA-06512: 在line 6
?
加个独立的块,
begin
select subnetype.subnemodel into v_spec from subnetype , subne
where subne.id = r.id and subne.subnetypeid = subnetype.id;
update asset set specformula = v_spec where id = r.subneassetid and specformula is null;
exception?
when?no_data_found?then
? ?null;
end;
这样在no_data_found时,循环就不会跳出了!
?
?