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- 使用分析函数来为记录排名的有关问题
日期:2014-05-16 浏览次数:20714 次
使用分析函数来为记录排名的问题
[size=large]现在有三个表student,score,course
对应的建表语句如下:
CREATE TABLE student(
student_id NUMBER PRIMARY KEY,
student_name,VARCHAR2(30) NOT NULL)
CREATE TABLE score(
score_id NUMBER PRIMARY KEY,
student_id NUMBER,
course_id NUMBER,
score NUMBER)
CREATE TABLE course(
course_id NUMBER PRIMARY KEY,
course_name VARCHAR2(30))
要求用基本SQL实现如下的两条查询要求:
(1) 求出每门课程成绩排名前五名的同学的姓名,分数和课程名
(2)求出每门课程成绩排名第三的同学的姓名,分数和课程名
Oracle的解法:
表及数据:
Sql代码
<SPAN style="FONT-SIZE: large">create table STUDENT
(
STUDENT_ID NUMBER not null,
STUDENT_NAME VARCHAR2(30) not null
)
;
alter table STUDENT
add primary key (STUDENT_ID);
prompt Loading STUDENT...
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (1, '张三');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (2, '李四');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (3, '王五');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (4, '马六');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (5, '孙七');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (6, '王八');
commit;</SPAN>
create table STUDENT
(
STUDENT_ID NUMBER not null,
STUDENT_NAME VARCHAR2(30) not null
)
;
alter table STUDENT
add primary key (STUDENT_ID);
prompt Loading STUDENT...
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (1, '张三');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (2, '李四');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (3, '王五');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (4, '马六');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (5, '孙七');
insert into STUDENT (STUDENT_ID, STUDENT_NAME)
values (6, '王八');
commit; Sql代码
<SPAN style="FONT-SIZE: large">create table COURSE
(
COURSE_ID NUMBER not null,
COURSE_NAME VARCHAR2(30)
)
;
alter table COURSE
add primary key (COURSE_ID);
prompt Loading COURSE...
insert into COURSE (COURSE_ID, COURSE_NAME)
values (1, '语文');
insert into COURSE (COURSE_ID, COURSE_NAME)
values (2, '数学');
insert into COURSE (COURSE_ID, COURSE_NAME)
values (3, '英语');
commit;</SPAN>
create table COURSE
(
COURSE_ID NUMBER not null,
COURSE_NAME VARCHAR2(30)
)
;
alter table COURSE
add primary key (COURSE_ID);
prompt Loading COURSE...
insert into COURSE (COURSE_ID, COURSE_NAME)
values (1, '语文');
insert into COURSE (COURSE_ID, COURSE_NAME)
values (2, '数学');
insert into COURSE (COURSE_ID, COURSE_NAME)
values (3, '英语');
commit; Sql代码
<SPAN style="FONT-SIZE: large">create table SCORE
(
SCORE_ID NUMBER not null,
STUDENT_ID NUMBER,
COURSE_ID NUMBER,
SCORE NUMBER
)
;
alter table SCORE
 
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