以前对于XML如何存储数据很感兴味，特别是看到一个文章说，可以直接用XML代替SQL server2000用来存储数据和交互数据，目前还在研讨之中。终于把如何存取图像到xml的代码搞定：）

读取图像

//定义图像源与目标xml文件

string ImgFileName = @"d:\中国挪动暴强广告.JPG";

string XmlFileName = @"D:\img.xml";

XmlTextWriter aXmlTextWriter = new XmlTextWriter(XmlFileName, System.Text.Encoding.Default);

aXmlTextWriter.Formatting = Formatting.Indented;

try

{

aXmlTextWriter.WriteStartDocument();

aXmlTextWriter.WriteComment("Contains a BinHex JPEG image");

aXmlTextWriter.WriteStartElement("jpeg");

//下边就是通用的读取图像的代码

System.IO.FileInfo fi = new System.IO.FileInfo(ImgFileName);

int size = (int)fi.Length;

//read the jpeg file

byte []img = new byte[size];

System.IO.FileStream fs = new System.IO.FileStream(ImgFileName, System.IO.FileMode.Open);

System.IO.BinaryReader br = new System.IO.BinaryReader(fs);

img = br.ReadBytes(size);

br.Close();

//留意这里用的是BinHex编码

aXmlTextWriter.WriteBinHex(img,0,size);

aXmlTextWriter.WriteEndDocument();

}

catch(XmlException xmlE)

{

Response.Write(xmlE.Message);

}

finally

{

aXmlTextWriter.Close();

}

显示图像

简单的在窗口中放一个PictureBox,在一个按钮中写如下代码

string XmlFileName = @"D:\img.xml";

XmlTextReader aXmlTextReader = new XmlTextReader(XmlFileName);

aXmlTextReader.Read();

aXmlTextReader.MoveToContent();

if(aXmlTextReader.LocalName == "jpeg")

{

System.IO.FileInfo fi = new System.IO.FileInfo(XmlFileName);

int iSize = (int)fi.Length;

byte []img = new byte[iSize];

aXmlTextReader.ReadBinHex(img,0,iSize);

//Byte to image object

System.IO.MemoryStream ms = new System.IO.MemoryStream();

ms.Write(img,0,iSize);

Bitmap bmp = new Bitmap(ms);

ms.Close();

this.pictureBox1.Image = bmp;

}

aXmlTextReader.Close();

谢谢作者，哈哈，我“偷”过来，方便本人看;)