C#中我将四个panel叠在一起，location和size相同，然后换页？但是会出现问题，下面是代码，求各位高手帮忙分析一下，解决小弟的问题！
private int clickpage = 0;//点击次数；
  //下一页，方法。
  private void nextpage()
  {
  switch(clickpage)
  {
  case 1: 
  this.panel1.Visible=false;
  this.panel2.Visible=true; 
  this.button2.Enabled = true;
  break;
  case 2: 
  this.panel2.Visible=false;
  this.panel3.Visible=true;
  break;
  case 3: 
  this.panel3.Visible=false;
  this.panel4.Visible=true;
  this.button3.Enabled = false;
  break;
  default :
  break;
  }
  }
  //下一页
  private void button3_Click(object sender, EventArgs e)
  {
  clickpage++;
  this.nextpage();
  }

  //上一页 方法
  private void uppage()
  {
  switch(clickpage)
  {
  case 0: 
  this.panel1.Visible=true;
  this.panel2.Visible=false;
  this.button2.Enabled = false;
  break;
  case 1: 
  this.panel2.Visible=true;
  this.panel3.Visible=false;
  break;
  case 2: 
  this.panel3.Visible=true;
  this.panel4.Visible=false;
  this.button3.Enabled = true;
  break;
  default:
  break;
  }
 
  }
  //上一页
  private void button2_Click(object sender, EventArgs e)
  {
  clickpage--;
  uppage();
  }

------解决方案--------------------
把4个panel放在一个Panel[]数组中，有助于你的代码精练。
Panel[] panels = new Panel[]{panel1, panel2, panel3, panel4};
private void uppage()
｛
for(int i=0; i < 4;i ++)
panels[i].Visible = clickpage = i;
｝
------解决方案--------------------

C# code

switch(clickpage)
  {
  case 1:  
 
[color=#FF0000]  this.panel2.BringToFront(); [/color]
  this.button2.Enabled = true;
  break;
  case 2:  
  
 [color=#FF0000] this.panel3.BringToFront();[/color]
  break;
  case 3:  
[color=#FF0000]  this.panel4.BringToFront();[/color]
  this.button3.Enabled = false;
  break;
  default :
  break;
  }
  }