日期:2014-05-18 浏览次数:21245 次
             StreamReader reader = new StreamReader("c:\\1.xml");
             string source = reader.ReadToEnd();
------解决方案--------------------
接 bdmh
C# code
  XmlDocument xd = new XmlDocument();
   
                      xd.Load(source );                         
XmlNodeList xnl = xd.GetElementsByTagName("xxx");
                           NodeEntity ne = new NodeEntity();
                           foreach (XmlNode xn in xnl)
                           {
                               string pname  = xn.Attributes["OMG"].Value;
}