日期:2014-05-18 浏览次数:21177 次
uint gen_crc(byte[] frame)
{
    int frame_len = frame.Length;
    byte c;
    uint treat, bcrc;
    uint wcrc = 0;
    for (int i = 0; i < frame_len; i++)
    {
        c = frame[i];
        for (int j = 0; j < 8; j++)
        {
            treat = c & 0x80U;
            c <<= 1;
            bcrc = (wcrc >> 8) & 0x80;
            wcrc <<= 1;
            if (treat != bcrc)
            {
                wcrc ^= 0x1021;
            }
        }
    }
    return wcrc;
}
------解决方案--------------------
02 30 31 30 32 34 38 31 4D E5 03
分析一下,是这段“30 31 30 32 34 38 31”运算后才是“4D E5”
类型该换成unsigned short
unsigned short gen_crc(BYTE far *frame, short frame_len)
{
        BYTE c, treat, bcrc;
        unsigned short wcrc = 0;
        short i, j;
        for (i = 0; i < frame_len; i++)
        {
                c = frame[i];
                for (j = 0; j  < 8; j++)
                {
                        treat = c & 0x80;
                        c  <<= 1;
                        bcrc = (wcrc >> 8) & 0x80;
                        wcrc  <<= 1;
                        if (treat != bcrc)
                                wcrc ^= 0x1021;
                }
        }
        return wcrc;
}