java中如何统计输入的次数
public class Text
{
 public ststic void main(String[] args)
  {
 String ansname
  int i
  int num =0
for(i=1;i<=32;i++)
{
System.out.println("Enter a competitor's name( type 'end' to finish):");  
  ansname = input.next();

if ("end".equalsIgnoreCase(ansname))
  {
  break;
  }
  }
  num=?
 }
}

  num为输入的次数,怎么显示输入次数

------解决方案--------------------
package com.cslg.xuxing.cn;

public class Demo02 {
public static void main(String[] args) { 
String ansname;
int i; 
int num =0; 
for(i=1;i <=32;i++) 
{ 
System.out.println("Enter a competitor's name( type 'end' to finish):");
ansname = input.next(); 
num++;
if("end".equalsIgnoreCase(ansname)) { 
break; 
} 
} 
Systen.out.println("输入次数"+num);
} 
}
ansname = input.next(); 这个我不是太明白，你能不能说明一下呀！ 


------解决方案--------------------
import java.util.*;

public class Text {
public static int Print(String name) {
int num = 0;
int n = name.indexOf(" ");
while (n != -1) {
name = name.trim();
n = name.indexOf(" ");
if (n != -1 && name.substring(0, n).length() > 0)
num++;
if (n != -1)
name = name.substring(n, name.length());
}
return num + 1;
}

public static void main(String[] args) {
Scanner Jie = new Scanner(System.in);
System.out
.println("Enter a competitor's name( type 'Enter' to finish):");
String name = Jie.nextLine();
System.out.println(Print(name));
}
}
不知道楼主是怎么想的，for(i=1;i <=32;i++)
if ("end".equalsIgnoreCase(ansname)) 
{ 
break; 
看不懂。
------解决方案--------------------

Java code

public static void main(String[] args) {

        String ansname;
        int i;
        int num = 0;
        Scanner input = new Scanner(System.in);//获得输入
        for (i = 1; i <= 32; i++) {
            System.out
                    .println("Enter a competitor's name(    type 'end' to finish):");

            ansname = input.next();//取得下一行

            if ("end".equalsIgnoreCase(ansname)) {
                break;
            }
            num++;
        }
        System.out.println("你输入" + num + "次");//输出次数
    }