一个js问题 跳出js的for循环
 怎么跳出js的for循环，其中id的大小不定

function CZY(){
    var stringC;
    for(var i=1;i<100;i++){
          
           var breaks = document.getElementById("breaks"+i).value;
           var s = document.getElementById("statusZY"+i).value;
           var casesInfoId = document.getElementById("casesInfoIdzy"+i).value;
           var statejbo = document.getElementById("statezyo"+i).value;
           var statejbt = document.getElementById("statezyt"+i).value;
           var statejbo1 = document.getElementById("statezyo"+i);
           var statejbt1 = document.getElementById("statezyt"+i);
           if(s==20){
              stringC+=s+"@"+casesInfoId+","; 
           }
           if(s==1){
              if(statejbo1.checked){
                   stringC+=statejbo+"@"+casesInfoId+",";
              }
              if(statejbt1.checked){ 
                   stringC+=statejbt+"@"+casesInfoId+",";  
              }
           }
           if(stringC=='undefined'){
              stringC="";
           }
           
      } 
         stringC=stringC.replace("undefined","");
         stringC=stringC.substr(0,stringC.length-1);
         ajaxT(stringC);
}


<tr>
                    <td align="right">审核：</td>
                    <td colspan="3">
                        <select id="statusZY<%=ZYo++%>" name="businessState" onchange="statusTFZY(<s:property value="baseCaseInfoID"/>)">
                             <option value="0">请选择</option>