SimpleDateFormat sd = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String temp = rs.getString(3);
Date date = sd.parse(temp);

------解决方案--------------------
SimpleDateFormat sd = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date d = sd.parse("2009-08-05 17:36:00");

------解决方案--------------------
如果你数据库中时date型，
String temp = rs.getString(3); 改成rs.getDate(3)
如果数据库中是varchar
Java code

import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;

public class test {
    public static void main(String[] args) throws Exception {
            DateFormat fmt =new SimpleDateFormat("yyyy-MM-dd");            
            String s = "1987-10-10";
            Date date = fmt.parse(s);
            System.out.println(fmt.format(date));
    }
}

------解决方案--------------------
SimpleDateFormat