日期:2014-05-17 浏览次数:21188 次
List<Map<String,String>> list = new ArrayList<Map<String,String>>();
Map map = new HashMap();
map.put("e_name","zhangsan");
map.put("c_name","张三");
map.put("bth_day","19811224");
map.put("sex","女");
list.add(map);
map = new HashMap();
map.put("e_name","lisi");
map.put("c_name","李四");
map.put("bth_day","19770805");
map.put("sex","男");
list.add(map);
map = new HashMap();
map.put("e_name","wangwu");
map.put("c_name","王五");
map.put("bth_day","19830924");
map.put("sex","女");
list.add(map);
------解决方案--------------------
<%@ page language="java" import="task6.MyList,java.util.List" pageEncoding="UTF-8"%>
<HTML>
<BODY>
<jsp:useBean id="mylist" scope="application" class="task6.MyList" >
</jsp:useBean>
<H3>MyList scope="request" Example</H3>
<table border=1>
<tr>
<td> 英文</td>
<td> 中文</td>
<td> 生日</td>
<td> 性别</td>
</tr>
<%
List list = mylist.getList() ;
int idx1 = 0;
int idx2 = 1;
int idx3 = 2;
int idx4 = 3;
int len = list.size() / 4;
for (int i = 0; i < len -1; i++){
%>
<tr>
<td><%=(String)list.get(idx1)%></td>
<td><%=(String)list.get(idx2)%></td>
<td><%=(String)list.get(idx3)%></td>
<td><%=(String)list.get(idx4)%></td>
</tr>
<%
idx1 +=4 ;
idx2 +=4 ;
idx3 +=4 ;
idx4 +=4 ;
}
%>
</table>
</BODY>
</HTML>
------解决方案--------------------
<body>
<table border="1px&qu