日期:2014-05-19  浏览次数:20553 次

判断用户登录,空值错误,在线等
实现中: 
Java code

    @Override
    public boolean isLogin(String username, String password) {
        
        boolean flag=false;
        String hql="select u.username,u.password from User u where u.username='"+username+"' and u.password='"+password+"'";
        System.out.println(username);
        System.out.println(password);
        List<User> list=hibernateTemplate.find(hql,new Object[]{username,password});
        if(list.size()>0 ){
            flag=true;
        }
        return flag;
    }



测试中: 

Java code
    @Test
    public void testIsLogin(){
        UserDaoImpl obj=new UserDaoImpl();
        obj.isLogin("a","a");
    }




------解决方案--------------------
为什么不用hibernate来持久化呢