日期:2014-05-20 浏览次数:20845 次
int[] ary = new int[100];
int sum1 = 0;
int sum2 = 0;
for (int i = 0; i < ary.length; i++) {
sum1 += i + 1;
sum2 += ary[i];
}
int rs = sum1 - sum2;
------解决方案--------------------
int[] ary = new int[99];
//给ary的每一个元素赋值......
int x = 5050; //写成int sum=(100+1)*100/2;也行.
for (int i = 0; i < ary.length; i++) {
x-=ary[i];
}
System.out.println("那个数是:"+x);