日期:2014-05-20 浏览次数:20893 次
public class TestDeadLock implements Runnable{
public int flag = 2;
static Object o1 = new Object();
static Object o2 = new Object();
public void run(){
if(flag == 1){
synchronized(o1){
System.out.println("锁住o1");
try {
Thread.sleep(5000);
}catch(Exception e){}
}
synchronized(o2){
System.out.println("1");
}
}
//疑问:无法死锁
if(flag == 0){
synchronized(o2){
System.out.println("锁住o2");
try {
Thread.sleep(5000);
}catch(Exception e){}
}
synchronized(o1){
System.out.println("2");
}
}
}
public static void main(String[] args){
TestDeadLock td1 = new TestDeadLock();
TestDeadLock td2 = new TestDeadLock();
td1.flag = 1;
td2.flag = 0;
Thread t1 = new Thread(td1);
Thread t2 = new Thread(td2);
t1.start();
t2.start();
}
}
public class TestDeadLock implements Runnable{
public int flag = 2;
static Object o1 = new Object();
static Object o2 = new Object();
public void run(){
if(flag == 1){
synchronized(o1){
System.out.println("锁住o1");
try {
Thread.sleep(5000);
}catch(Exception e){}
synchronized(o2){
System.out.println("1");
}
}
}
//疑问:无法死锁
if(flag == 0){
synchronized(o2){
System.out.println("锁住o2");
try {
Thread.sleep(5000);
}catch(Exception e){}
synchronized(o1){
System.out.println("2");
}
}
}
}
public static void main(String[] args){
TestDeadLock td1 = new TestDeadLock();
TestDeadLock td2 = new TestDeadLock();
td1.flag = 1;
td2.flag = 0;
Thread t1 = new Thread(td1);
Thread t2 = new Thread(td2);
t1.start();
t2.start();
}
}
------解决方案--------------------
顶1 楼的,LZ你的代码,把第二个sychronized 放在外面,这样的话,就不是用sychronized code(同步代码块),用sychronized method(同步函数)来解决,我们平常,写代码,是为了不让其死锁!
------解决方案--------------------