public static void main(String[] args) throws ParseException {
        String testStr = "\"aabs.333\",\"aac.11\",\"111ddddd.3122\"";
        String reg = "\"[^\\.]*\\.([^\"]+)\"";
        Pattern p = Pattern.compile(reg);
        Matcher matcher = p.matcher(testStr);
        while (matcher.find()) {
            System.out.println(matcher.group(1));
        }
    }

------解决方案--------------------
很赞！
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大概是：
str = str.replaceAll("[^\\.]*\\.(\\d*).*", "$1");
System.out.println(str);


------解决方案--------------------
Java code

System.out.println("aabs.333".substring("aabs.333".lastIndexOf(".")+1));

------解决方案--------------------
只满足LZ的需求的话很简单：
Java code

    public static void main(String[] args) {
        String strings[] = { "aabs.333", "aac.11", "111ddddd.3122" };

        for (String str : strings) {
            if (str.contains("."))
                System.out.println(str.substring(str.lastIndexOf('.') + 1));
        }
    }