日期:2014-05-20 浏览次数:21052 次
String str = "23578075;677449,9865333qweeqweq;(陈)6789,sdfas ";
Matcher m = Pattern.compile("[,,;;()()](\\d{4})[,,;;()()]").matcher(str);
while(m.find())
System.out.println(m.group(1));
------解决方案--------------------
用正则表达式应该很容易做到,下面是我的实验代码,请高手指教
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Test3 {
public static void main(String[] args) {
String str = "23578075;677449,9865333,qweeqweq;(陈)6789,sdfas 1234";
String regex = "\\b\\d{4}\\b";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(str);
while(m.find()) {
System.out.println(m.group());
}
}
}