日期:2014-05-20 浏览次数:21033 次
import java.io.IOException; import java.util.Scanner; public class Main { public static void main(String[] args) throws IOException { String num1, num2; // user String to save **** int Scanner in = new Scanner(System.in); num1 = in.nextLine(); num2 = in.nextLine(); int A = 0, B = 0; for (int i = 0; i < 4; i++) { for (int j = 0; j < 4; j++) { if (num1.charAt(i) == num2.charAt(j)) B++; } } for (int i = 0; i < 4; i++) { if (num1.charAt(i) == num2.charAt(i)) A++; } System.out.println(A + "A" + (B - A) + "B"); } }
------解决方案--------------------
public static void main(String[] args) {
int a = 5673;
int b = 5013;
HashMap list = new HashMap();
while (a > 0) {
list.put(list.size(), a % 10);
a /= 10;
}
int k1 = 0, k2 = 0;
int i = 0;
while (b > 0) {
int t = b % 10;
if (list.containsValue(t)) {
if (list.get(i) == Integer.valueOf(t))
k1++;
else
k2++;
}
i++;
b /= 10;
}
System.out.println(k1 + "A" + k2 + "B");
}
------解决方案--------------------
int A = 0;
int B = 0;
String s1 = "5673";
String s2 = "0153";
if(s1.length() == s2.length()) {
for(int i = 0; i < s1.length(); i++) {
char c1 = s1.charAt(i);
for(int j = 0; j < s2.length(); j++) {
char c2 = s2.charAt(j);
if(c1 == c2) {
if(i == j) {
A++;
}
else {
B++;
}
}
}
}
}
System.err.println(A + "A" + B + "B");
------解决方案--------------------
public static void main(String[] args){
int a = 0, b = 0;
String s1 = "5673";
String s2 = "5013";
for (int j = 0, i = 0; i<s1.length();)
{
if (s1.charAt(i)==s2.charAt(j)){
if (i==j){
a++;
}
else{
b++;
}
}
j++;
if (j==s1.length()){
i++;
j = 0;
}
}
System.out.println(a+"A"+b+"B");
}
------解决方案--------------------
char [] num1 = new Integer(5673).toString().toCharArray();
char [] num2 = new Integer(5013).toString().toCharArray();
int counterA = 0, counterB = 0;
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 4; j++) {
if (j!=i&&num1[i] == num2[j])
counterB++;
}
if (num1[i] == num2[i] )counterA++;
}
System.out.println(counterA + "A" + counterB + "B");