String str =fdsaf2006060743242 
Pattern p = Pattern.compile("[1-2][0-9]{3}[0-1][0-9][0-3][0-9]?", Pattern.CASE_INSENSITIVE);
 Matcher m = p.matcher(ss);
 while (m.find()) {
  String s = m.group();
  String y = s.substring(0, 4);
  String mon = s.substring(4, 6);
  String date = s.substring(6, 8);
  s = y + "-" + mon + "-" + date;
        }
    }

------解决方案--------------------
Java code

    public static String formatDateStr(String src)
    {
        SimpleDateFormat format = new SimpleDateFormat("yyyyMMdd");
        String ret = "";
        
        try
        {
            Calendar calendar = Calendar.getInstance();
            calendar.setTime(format.parse(src.trim()));
            int year = calendar.get(Calendar.YEAR);
            int month = calendar.get(Calendar.MONTH) + 1;
            int day = calendar.get(Calendar.DAY_OF_MONTH);
            ret = year + "-" + (month < 10? "0" + month: month) + "-" + (day < 10? "0" + day: day);
        }
        catch(ParseException e)
        {
            e.printStackTrace();
        }
        
        return ret;
    }

------解决方案--------------------
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引用:
Java codepublicstaticvoidmain(String[] args) { 
        System.out.println(formatString("20060603")); 
        System.out.println(formatString("20070503")); 
        System.out.println(formatString("20080208")); 
    }publicstaticString formatString(String value) {returnvalue.replaceAll("(? <=[1-9])0(?!0)","-0"); 
    } 
 
如果是20080412,20081101,20081111, 
…