回文问题，求助
class TJ4_5{
public static void main(String args[]){
String s="Madam I'm Adam",s2,s3,s4;
char a[]=s.toCharArray(),temp;
char s1[]=new char[s.length()];
char c[]=new char[s.length()];
char d[]=new char[s.length()];
for(int i=0;i<s.length();i++){
if(Character.isLetterOrDigit(a[i])){
s1[i]=a[i];
}
}
s2=new String(s1);
if(s2.length()%2==0){
s2.getChars(0,s2.length()/2,c,0);
s2.getChars(s2.length()/2,s2.length(),d,0);
System.out.println(c); //交换前的c字符串
System.out.println(d); //交换前的c字符串
}
else{
s2.getChars(0,s2.length()/2,c,0);
s2.getChars(s2.length()/2+1,s2.length(),d,0);
System.out.println(c); //交换前的c字符串
System.out.println(d); //交换前的d字符串
}
for(int i=0;i<d.length/2;i++){
temp=d[i];
d[i]=d[d.length-i-1];
d[d.length-i-1]=temp;
}
s3=new String(c);
s4=new String(d);
System.out.println(s4);
if(s3.equalsIgnoreCase(s4)){
System.out.println("是回文");
}
else{
System.out.println("不是回文");
}
}
}
这个程序在字符串转化为数组之后，数组长度一直是14（字符串的长度），为什么在把a数组赋给s1数组之后长度还是没有变化？请问应该如何更改程序，才能是结果正常？

------解决方案--------------------
你结果是要做什么呢？说实话对字符串数字奇偶的判别处想要作什么不是很清楚
如果是回文处理，逆序字符串即可做到啊
------解决方案--------------------
char c[]=new char[s.length()]; 
char d[]=new char[s.length()]; 
这是长度不变化的原因~

你这个方法实在是..不想改..重新写个新的好了

Java code

class TJ4_5 {
    public static void main(String args[]) {
        String s = "Madam I'm Adam";
        String s1 = new String();
        String s2 = new String();
        char a[] = s.toCharArray();
        for (int i = 0; i < a.length; i++)
            if (Character.isLetterOrDigit(a[i])) {
                s1 = s1 + a[i];
                s2 = a[i] + s2;
            }
        if (s1.equalsIgnoreCase(s2))
            System.out.println("是回文");
        else
            System.out.println("不是回文");
    }
}

------解决方案--------------------
修改了一下`
[code=Java]import java.awt.*;
public class HuiWen {

	/**
	 * @langzi
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
    String str = "aabbcc";
    String s1 = new String();
    String s2 = new String();
    char c[] = str.toCharArray();
    for(int i = 0 ; i < str.length();i++){
   	 if(Character.isLetterOrDigit(c[i])){
   		 s1 =  s1 + c[i];
   		 s2 =  c[i] + s2;
   	 }
   	 s1 = new String(s1);
   	 s2 = new String(s2);
    }
   			if(s1.equalsIgnoreCase(s2)){
   				System.out.println("is huiwen");
   			}
   			else
   				System.out.println("is not huiwen");
    }
}
[/java]