日期:2014-05-17 浏览次数:20803 次
<tr> <td height="62" background="images/office_r9_c7.jpg" width="871"> <a href="of_detail.jsp?id=<%=news.getID() %>"class="pt1"> <div align="center" class="bluept"><%=news.getTITLE() %></div></a> </td> <td height="62" background="images/office_r9_c7.jpg" width="871"> <a href="of_detail.jsp?id=<%=news.getID() %>"class="pt1"> <div align="center" class="bluept"><%=news.getTITLE() %></div></a> </td> </tr>
------解决方案--------------------
每两个换行吗?
<%
for(int i =0;i<list.size();i++){
News news = (News)list.get(i);
if(i%2==0)  {
%>
<tr> <%}%>
  <td height="62" background="images/office_r9_c7.jpg" width="871">
  <a href="of_detail.jsp?id=<%=news.getID() %>"class="pt1">
  <div align="center" class="bluept"><%=news.getTITLE() %></div></a>
  </td>
<% if((i+1)%2==0)  {
  </tr> <%}%>
  <%} %>
------解决方案--------------------
楼主怎么又发一次?
<%  
  boolean flag = true;
  for(int i =0;i<list.size();i++){
  ea =(Expert_team)list.get(i);
    
  if(flag){
  %>
  <tr>
  <td><%=ea.getNAME()%><%flag=false;%></td>
  
  <%}else{%>
 <td><%=ea.getNAME()%><%flag=true;%></td></tr>
  <%
  }  }
  %>
------解决方案--------------------
<%
  for(int i =0;i<list.size();i+=2){
  // 第一列
  News news = (News)list.get(i);  
   
  //第二列
  if(i+1<list.size()) {
     news = (News)list.get(i+1);  
  }else {
     //<td> </td>
  }
%>
------解决方案--------------------