String aa = "abaacabdcabd";
            String[] bb = aa.split("ab");
            int count = bb.length-1;
            System.out.println(count);

------解决方案--------------------
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引用:

1、Java code
String aa = "abaacabdcabd";
String[] bb = aa.split("ab");
int count = bb.length-1;
System.out.println(count);


2、Java code
LinkedList<Integer> lis……
……


------解决方案--------------------
String aa = "aaaaaaab";
String bb = "aa";

------解决方案--------------------

Java code
/**
     * 链表去重及倒置
     */
    public static LinkedList<Integer> offer(LinkedList<Integer> e) {
        Map<Integer, Integer> map = new HashMap<Integer, Integer>();
        LinkedList<Integer> list = new LinkedList<Integer>();
        Integer i;
        for (Integer r : e) {
            if (map.containsKey(r))
                map.put(r, map.get(r) + 1);
            else
                map.put(r, 1);
        }

        for (Integer j : map.keySet()) {
            if (map.get(j) == 1)
                list.add(j);
        }

        Collections.reverse(list);
        return list;
    }