日期:2014-05-16 浏览次数:20961 次
SELECT Course_Name, ( SELECT count( * ) FROM `enrolled` GROUP BY Course_Uid ) FROM course WHERE Course_Uid IN ( SELECT Course_Uid FROM enrolled GROUP BY Course_Uid );
select a.course_uid,a.course_name,count(b.student_uid) cout
from course a,enrolled b 
where a.course_uid=b.course_uid
group by a.course_uid;