oracle job 简单作业调用存储过程
    --------------------------------
--创建一个存储过程、用来给oracle作业调用
--------------------------------
create or replace procedure PLAN_AUTO_FACTTIME_PROC
(time_plan_lastDay in varchar2,fact_cost_am in number,fact_cost_pm in number) is
i number;
previous_day varchar2(50);
begin
i:=1;
loop
  i:=i+1;
  select to_date(time_plan_lastDay,'yyyy-mm-dd')-i into previous_day from dual;  
  ddl...;
  if i>6 then
    exit;
  end if;
end loop;
end;
-----------------------------------
-----在命令窗口下执行正确的oracle作业创建及启动
SQL>  variable jobno  number ;
SQL> begin
  2  dbms_job.submit(job => :jobno,
  3   what => 'PLAN_AUTO_FACTTIME_PROC(''2012-4-8'',210,270);',
  4  next_date => sysdate,
  5  interval => 'sysdate+1/1440');//调用周期设置
  6  commit;
  7  end;
  8  /
----- 启动
begin
dbms_job.run(:jobno);
end;
-----删除
begin
dbms_job.remove(:jobno);
end;
-----停止
begin
dbms_job.broken(:jobno);
end;
---------------------------------
我的异常网推荐解决方案:oracle存储过程,http://www.aiyiweb.com/oracle-develop/177537.html