javaBean的工作机制是什么？小弟我的javabean如何总是报错
日期：2014-05-18 浏览次数：20698 次
javaBean的工作机制是什么？我的javabean怎么总是报错？
jsp页面：--------------
<%@ page contentType= "text/html; charset=gb2312 " language= "java " import= "java.sql.* " errorPage= "error.jsp " %>
<!--创建并调用bean(counter)-->
<jsp:useBean id= "counter " scope= "request " class= "Counter ">
</jsp:useBean>
<html>
<head>
<title> 出错演示 </title>
<meta http-equiv= "Content-Type " content= "text/html; charset=gb2312 ">
</head>
<body>
</body>
</html>
javabean文件：-----------
//counter.java 读写文件的一个bean
import java.io.*;
public class counter extends object {
private string currentrecord = null;//保存文本的变量
private bufferedreader file; //bufferedreader对象，用于读取文件数据
private string path;//文件完整路径名
public counter() {
}
//readfile方法用来读取文件filepath中的数据，并返回这个数据
public string readfile(string filepath) throws filenotfoundexception
{
path = filepath;
//创建新的bufferedreader对象
file = new bufferedreader(new filereader(path));
string returnstr =null;
try
{
//读取一行数据并保存到currentrecord变量中
currentrecord = file.readline();
}
catch (ioexception e)
{//错误处理
system.out.println( "读取数据错误. ");
}
if (currentrecord == null)
//如果文件为空
returnstr = "没有任何记录 ";
else
{//文件不为空
returnstr =currentrecord;
}
//返回读取文件的数据
return returnstr;
}
//readfile方法用来将数据counter+1后写入到文本文件filepath中
//以实现计数增长的功能
public void writefile(string filepath,string counter) throws
filenotfoundexception
{
path = filepath;
//将counter转换为int类型并加一
int writestr = integer.parseint(counter)+1;
try {
//创建printwriter对象，用于写入数据到文件中
printwriter pw = new printwriter(new fileoutputstream(filepath));
//用文本格式打印整数writestr
pw.println(writestr);
//清除printwriter对象
pw.close();
} catch(ioexception e) {
//错误处理
system.out.println( "写入文件错误 "+e.getmessage());
}
}
}
最后报错的内容是：--------
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 3 in the jsp file: /test.jsp
Generated servlet error:
[javac] Compiling 1 source file
D:\server\Tomcat\work\Catalina\localhost\jsq\org\apache\jsp\test_jsp.java:42: cannot resolve symbol
symbol : class Counter
location: class org.apache.jsp.test_jsp
Counter counter = null;
^
An error
jsp页面：--------------
<%@ page contentType= "text/html; charset=gb2312 " language= "java " import= "java.sql.* " errorPage= "error.jsp " %>
<!--创建并调用bean(counter)-->
<jsp:useBean id= "counter " scope= "request " class= "Counter ">
</jsp:useBean>
<html>
<head>
<title> 出错演示 </title>
<meta http-equiv= "Content-Type " content= "text/html; charset=gb2312 ">
</head>
<body>
</body>
</html>
javabean文件：-----------
//counter.java 读写文件的一个bean
import java.io.*;
public class counter extends object {
private string currentrecord = null;//保存文本的变量
private bufferedreader file; //bufferedreader对象，用于读取文件数据
private string path;//文件完整路径名
public counter() {
}
//readfile方法用来读取文件filepath中的数据，并返回这个数据
public string readfile(string filepath) throws filenotfoundexception
{
path = filepath;
//创建新的bufferedreader对象
file = new bufferedreader(new filereader(path));
string returnstr =null;
try
{
//读取一行数据并保存到currentrecord变量中
currentrecord = file.readline();
}
catch (ioexception e)
{//错误处理
system.out.println( "读取数据错误. ");
}
if (currentrecord == null)
//如果文件为空
returnstr = "没有任何记录 ";
else
{//文件不为空
returnstr =currentrecord;
}
//返回读取文件的数据
return returnstr;
}
//readfile方法用来将数据counter+1后写入到文本文件filepath中
//以实现计数增长的功能
public void writefile(string filepath,string counter) throws
filenotfoundexception
{
path = filepath;
//将counter转换为int类型并加一
int writestr = integer.parseint(counter)+1;
try {
//创建printwriter对象，用于写入数据到文件中
printwriter pw = new printwriter(new fileoutputstream(filepath));
//用文本格式打印整数writestr
pw.println(writestr);
//清除printwriter对象
pw.close();
} catch(ioexception e) {
//错误处理
system.out.println( "写入文件错误 "+e.getmessage());
}
}
}
最后报错的内容是：--------
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 3 in the jsp file: /test.jsp
Generated servlet error:
[javac] Compiling 1 source file
D:\server\Tomcat\work\Catalina\localhost\jsq\org\apache\jsp\test_jsp.java:42: cannot resolve symbol
symbol : class Counter
location: class org.apache.jsp.test_jsp
Counter counter = null;
^
An error
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