日期:2014-05-20  浏览次数:20603 次

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将1~9这九个数字填入九个空格中。每一横行的三个数字组成一个三位数。如果要使第二行的三位数是第一行的两倍, 第三行的三位数是第一行的三倍, 应怎样填数。
 

------解决方案--------------------
Java code

package com.esen.chenf.test;

public class Test8 {
    public static void main(String[] args) {
        int[][] a = new int[10][2];
        int num1 = 0, num2 = 0, num3 = 0;
        for (int i = 0; i < 9; i++) {
            for (int j = 0; j < 9; j++) {
                for (int k = 0; k < 9; k++) {
                    init(a);
                    if (a[i][1] == 0 && a[j][1] == 0 && a[k][1] == 0) {
                        num1 = a[i][0] * 100 + a[j][0] * 10 + a[k][0];
                        a[i][1] = 1;
                        a[j][1] = 1;
                        a[k][1] = 1;
                    }
                    num2 = num1 * 2;
                    if(!avaliable(num2, a)){
                        continue;
                    }
                    num3 = num1*3;
                    if(!avaliable(num3, a)){
                        continue;
                    }
                    System.out.println(num1);
                    System.out.println(num2);
                    System.out.println(num3);
                }
            }
        }
    }

    private static void init(int[][] a) {
        for (int i = 0; i < 9; i++) {
            a[i][0] = i + 1;
            a[i][1] = 0;
        }
    }

    public static boolean avaliable(int num, int[][] a) {
        if (num < 100 || num >= 1000)
            return false;
        for (int i = 0; i < 3; i++) {
            int k = num % 10 - 1;
            if(k == -1)
                return false;
            if (a[k][1] == 1)
                return false;
            a[k][1] = 1;
            num /= 10;
        }
        return true;
    }
}

------解决方案--------------------
for example
Java code
int[] sum = new int[3];
int[][] matrix = new int[3][3];
List<Integer> list = new ArrayList<Integer>();
for (int i=123, cnt=1; i<333; i++) {
    sum[0] = i;
    sum[1] = i*2;
    sum[2] = i*3;
    list.clear();
    for (int j=0, k=100, v=0; j<sum.length; j++, k=100) {
        while (k > 0) {
            v = sum[j]/k;
            sum[j] %= k;
            k /= 10;
            if (! list.contains(v) && v != 0) {list.add(v);}
        }
    }
    if (list.size() == 9) {
        System.out.printf("matrix-%d\n", cnt++);
        for (int j=0; j<list.size(); j++) {
            matrix[j/3][j%3] = list.get(j);
            System.out.printf("%d", list.get(j));
            if ((j+1)%3 == 0) {System.out.println();}
         }
    }
}

------解决方案--------------------
别把问题想复杂了

Java code

public static void main(String[] args) {
        int m = 0;
        int n = 0;
        String str = null;
        for(int i=123;i<345;i++){
            m = i*2;
            n = i*3;
            str = "" + i + m + n;
            byte[] b = str.getBytes();
            Arrays.sort(b);
            str = new String(b);
            if("123456789".equals(str)){
                System.out.println(i + ";" + m + ";" + n);
            }
        }
    }