import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import java.util.Random;


/**
 * 不规则列表的数据起止判定
 * @author jinxfei
 *
 */
public class BGZList {

    private static Random r=new Random(System.currentTimeMillis());
    
    public static void main(String[] args) throws Exception{
        List<Integer> targetList=createBGZList();
        System.out.println("随机数组：\n"+targetList);
        System.out.println("请输入起始值：\n");
        BufferedReader r=new BufferedReader(new InputStreamReader(System.in));
        int start=Integer.parseInt(r.readLine());
        System.out.println("请输入终止值：\n");        
        int end=Integer.parseInt(r.readLine());
        end-=start;
        int startIndex=0,startPos=0;
        int endIndex=0,endPos=0;
        for(int i=0; i<targetList.size();i++){
            Integer cur=targetList.get(i);
            if (start>=0){
                if (start>cur){
                    start-=cur;                    
                    continue;
                }            
                startIndex=i+1;
                startPos=start;
                start=-1;
            }else{
                if (end>cur){
                    end-=cur;
                    continue;
                }
                endIndex=i+1;
                endPos=end;
                break;
            }
            
        }
        System.out.println("开始于 "+startIndex+" 的 "+startPos+", 结束于 "+endIndex+" 的 "+endPos);
    }
    
    /**
     * 创建一个随机长度(10-110)的list，list中的每一个数字也都是随机的（5-55)，
     * 
     * @return
     */
    private static List<Integer> createBGZList(){
        List<Integer> result=new ArrayList<Integer>();
        int listLength=r.nextInt(100)+10;
        for(int i=0; i<listLength;i++){
            result.add(r.nextInt(50)+5);
        }
        return result;
    }
}

------解决方案--------------------
写好了，可能不是很规范 ，但可以得到结果。考到java里面直接可以运行

package a;

import java.util.ArrayList;
import java.util.List;

public class Test {

	public static List<int[]> list = new ArrayList<int[]>();

	public Test() {
		int[] a = { 1, 2, 3 };
		int[] b = { 4, 5, 6, 7, 8, 9, 10 };
		int[] c = { 11, 12, 13, 14 };
		list.add(a);
		list.add(b);
		list.add(c);
	}

	public int[] function(int x, int y) {
		int[] returnBack = new int[4];
		int[] a = get(x);
		int[] b = get(y);
		returnBack[0] = a[0];
		returnBack[1] = a[1];
		returnBack[2] = b[0];
		returnBack[3] = b[1];
		return returnBack;
	}

	public static int[] get(int x) {
		int[] returnBack = new int[2];
		int sum = 0;
		int cout = 0;
		for (int n = 0; n < list.size(); n++) {
			sum = sum + (list.get(n)).length;
			if (x <= sum && cout == 0) {
				cout++;
				returnBack[0] = n + 1;
				for (int i = 0; i < (list.get(n)).length; i++) {
					if (x == list.get(n)[i]) {
						returnBack[1] = i + 1;
					}
				}
			}
		}

		return returnBack;
	}

	public static void main(String[] args) {
		Test test = new Test();
		int[] aa = test.function(3, 14);

		for (int i = 0; i < aa.length; i++) {
			System.out.println(aa[i]);

		}
	}

}


------解决方案--------------------