日期:2014-05-16 浏览次数:20884 次
如果了解java多线程编程的话,照葫芦画瓢,是很容易理解linux下面的线程模型的。
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#include <pthread.h> #include <stdio.h> #include <unistd.h> //define the first thread procedure. void * thread_1_pro(void * arg) { //derive current thread's id pthread_t tid; tid=pthread_self(); printf(" AAAAA thread id is %u\n",(unsigned int)tid); int * p_int_a=(int *) arg; while(1) { sleep(5); printf("------------- a = %d\n",*p_int_a); (*p_int_a)++; printf("+++++++++++++ a = %d\n",*p_int_a); } } //define the second thread procedure. void * thread_2_pro(void * arg) { //derive current thread's id pthread_t tid; tid=pthread_self(); printf(" BBBB thread id is %u\n",(unsigned int)tid); int * p_int_a=(int *) arg; while(1) { sleep(3); printf("------------- b = %d\n",*p_int_a); (*p_int_a)++; printf("+++++++++++++ b = %d\n",*p_int_a); } } int main(int argc, char ** argv) { pthread_t tidA, tidB; //derive current thread's id pthread_t tid; tid=pthread_self(); printf(" CCCCCC thread id is %u\n",(unsigned int)tid); int common=0; pthread_create(&tidA, NULL, &thread_1_pro, &common); pthread_create(&tidB, NULL, &thread_2_pro, &common); sleep(12); //为什么需要最下面两行呢,如果没有,12秒后,主进程结束,会自动回收线程tidA, tidB, //这两行就是主进程中的线程要等这两个分支线程结束后,才执行join后面的内容。 //pthread_join(tidA, NULL); //pthread_join(tidB, NULL); return 0; }
?? 输出结果:
CCCCCC thread id is 3078366912 BBBB thread id is 3069971312 AAAAA thread id is 3078364016 ------------- b = 0 +++++++++++++ b = 1 ------------- a = 1 +++++++++++++ a = 2 ------------- b = 2 +++++++++++++ b = 3 ------------- b = 3 +++++++++++++ b = 4 ------------- a = 4 +++++++++++++ a = 5 ------------- b = 5 +++++++++++++ b = 6
??可以看到这个结果还是蛮有规律的,但是我们想说的,如果仔细调整一下sleep的位置,输出的结果可能就没有上面这么规律了,如下。
//define the first thread procedure. void * thread_1_pro(void * arg) { //derive current thread's id pthread_t tid; tid=pthread_self(); printf(" AAAAA thread id is %u\n",(unsigned int)tid); int * p_int_a=(int *) arg; while(1) { printf("------------- a = %d\n",*p_int_a); (*p_int_a)++; sleep(7); printf("+++++++++++++ a = %d\n",*p_int_a); } } //define the second thread procedure. void * thread_2_pro(void * arg) { //derive current thread's id pthread_t tid; tid=pthread_self(); printf(" BBBB thread id is %u\n",(unsigned int)tid); int * p_int_a=(int *) arg; while(1) { printf("------------- b = %d\n",*p_int_a); (*p_int_a)++; sleep(3); printf("+++++++++++++ b = %d\n",*p_int_a); } }
??输出的结果如下:
CCCCCC thread id is 3077633728 AAAAA thread id is 3077630832 ------------- a = 0 BBBB thread id is 3069238128 ------------- b = 1 +++++++++++++ b = 2 ------------- b = 2 +++++++++++++ b = 3 ------------- b = 3 +++++++++++++ a = 4 ------------- a = 4 +++++++++++++ b = 5 ------------- b = 5 +++++++++++++ b = 6 ------------- b = 6 +++++++++++++ a = 7 ------------- a = 7 +++++++++++++ b = 8 ------------- b = 8 +++++++++++++ b = 9 ------------- b = 9
?和上面相比,显的比较乱,是因为没有“同步”的原因。
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