SELECT 号码,时间,次数=(ROW_NUMBER()OVER(PARTITION BY 号码,ORDER BY 时间))-1  
FROM TABLEA ),
A2 AS(
SELECT 号码,MIN(时间) 
FROM TABLEA 
GROUP BY 号码

------解决方案--------------------
SQL code



DECLARE @t table
(
  number varchar(10),
  cdate datetime
)

INSERT INTO @t
  SELECT '123', '2012/2/13 16:23:12'
  UNION
  SELECT '234', '2012/2/25 16:23:12'
  UNION
  SELECT '123', '2012/5/13 16:23:12'
  UNION
  SELECT '235', '2011/2/13 16:23:12'
  UNION
  SELECT '321', '2012/1/15 16:23:12'
  UNION
  SELECT '234', '2012/2/17 16:23:12'
  UNION
  SELECT '123', '2012/2/13 20:11:01'
  UNION
  SELECT '321', '2012/1/10 16:23:12'
  
SELECT t1.number,t1.cdate, COUNT(t2.number)+1
FROM @t t1
LEFT JOIN @t t2 
ON t1.number=t2.number AND t1.cdate>t2.cdate

GROUP BY t1.number, t1.cdate, t2.number