日期:2014-05-18 浏览次数:20465 次
select * from a union all select * from b
------解决方案--------------------
select * from a
union all
select * from b
------解决方案--------------------
select * from
(
select * from a
union all
select * from b
) c
------解决方案--------------------
不去重复 union all
去重复 union
------解决方案--------------------
select * from a union all --加all不去重,直接union去重! select * from b
------解决方案--------------------
select * from a
union all
select * from b
------解决方案--------------------