1. select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/)
2. select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表 set rowcount n --只取n条结果 select * from 表变量 order by columnname desc
3. select top n * from (select top m * from tablename order by columnname) a order by columnname desc
4.如果tablename里没有其他identity列,那么: 先生成一个序列,存储在一临时表中. select identity(int) id0,* into #temp from tablename
取n到m条的语句为: select * from #temp where id0 > =n and id0 <= m
如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行: exec sp_dboption 你的DB名字,'select into/bulkcopy',true
5.如果表里有identity属性,那么简单: select * from tablename where identity_col between n and m
6.SQL2005开始.可以使用row_number() over()生成行号 ;with cte as ( select id0=row_number() over(order by id),* from tablename ) select * from cte where id0 between n to m ******说的是什么意思******
------解决方案-------------------- 这东西在oracle里是不是不好使
------解决方案-------------------- Oracle好像没有top这种语法。
------解决方案--------------------