日期:2014-05-18 浏览次数:20539 次
CREATE FUNCTION dbo.f_hex_dec(@s varchar(16)) RETURNS bigint AS BEGIN DECLARE @i int,@result bigint SELECT @i=0,@result=0,@s=RTRIM(LTRIM(UPPER(REVERSE(@s)))) WHILE @i<LEN(@s) BEGIN IF SUBSTRING(@s,@i+1,1) not between '0' and '9' and SUBSTRING(@s,@i+1,1) not between 'A' and 'F' BEGIN SELECT @result=0 break END SELECT @result=@result+(CHARINDEX(SUBSTRING(@s,@i+1,1),'0123456789ABCDEF')-1)*POWER(16,@i),@i=@i+1 END RETURN @result END GO
------解决方案--------------------
找到一个10转16的.
--创建16进制转换字符串函数
CREATE function fn_hex_to_char (
@x varbinary(100), -- binary hex value
@l int -- number of bytes
) returns varchar(200)
as
-- Written by: Gregory A. Larsen
-- Date: May 25, 2004
-- Description: This function will take any binary value and return
-- the hex value as a character representation.
-- In order to use this function you need to pass the
-- binary hex value and the number of bytes you want to
-- convert.
begin
declare @i varbinary(10)
declare @digits char(16)
set @digits = '0123456789ABCDEF'
declare @s varchar(100)
declare @h varchar(100)
declare @j int
set @j = 0
set @h = ''
-- process all bytes
while @j < @l
begin
set @j= @j + 1
-- get first character of byte
set @i = substring(cast(@x as varbinary(100)),@j,1)
-- get the first character
set @s = cast(substring(@digits,@i%16+1,1) as char(1))
-- shift over one character
set @i = @i/16
-- get the second character
set @s = cast(substring(@digits,@i%16+1,1) as char(1)) + @s
-- build string of hex characters
set @h = @h + @s
end
return(@h)
end
go
--调用
select dbo.fn_hex_to_char(convert(varbinary,100),4)