日期:2014-05-17  浏览次数:20884 次

这段java代码用存储过程怎么写
这段java代码用存储过程怎么写:
public String function_A( String table_name , String obid ) {

  Statement stmt = null;
  ResultSet rs = null;

  String sql = "select * from" + table_name+ "where OBID='"+obid+"'" ;
  rs = stmt.executeQuery( sql ) ;
  
  return rs.getString( "STUDENT_NAME" );
}

------解决方案--------------------
我的异常网推荐解决方案:oracle存储过程,http://www.aiyiweb.com/oracle-develop/177537.html
------解决方案--------------------
Java code
一:无返回值的存储过程

存储过程为:

CREATE OR REPLACE PROCEDURE TESTA(PARA1 IN VARCHAR2,PARA2 IN VARCHAR2)  AS

BEGIN

   INSERT INTO HYQ.B_ID (I_ID,I_NAME) VALUES (PARA1, PARA2);

END TESTA;

然后呢,在java里调用时就用下面的代码:

package com.hyq.src;

 

import java.sql.*;

import java.sql.ResultSet;

 

public class TestProcedureOne {

  public TestProcedureOne() {

  }

  public static void main(String[] args ){

    String driver = "oracle.jdbc.driver.OracleDriver";

    String strUrl = "jdbc:oracle:thin:@127.0.0.1:1521: hyq ";

    Statement stmt = null;

    ResultSet rs = null;

    Connection conn = null;

    CallableStatement cstmt = null;

 

    try {

      Class.forName(driver);

      conn =  DriverManager.getConnection(strUrl, " hyq ", " hyq ");

      CallableStatement proc = null;

      proc = conn.prepareCall("{ call HYQ.TESTA(?,?) }");

      proc.setString(1, "100");

      proc.setString(2, "TestOne");

      proc.execute();

    }

    catch (SQLException ex2) {

      ex2.printStackTrace();

    }

    catch (Exception ex2) {

      ex2.printStackTrace();

    }

    finally{

      try {

        if(rs != null){

          rs.close();

          if(stmt!=null){

            stmt.close();

          }

          if(conn!=null){

            conn.close();

          }

        }

      }

      catch (SQLException ex1) {

      }

    }

  }

}