日期:2014-05-16 浏览次数:20381 次
1、插入数据
>>> from books.models import Publisher >>> p1 = Publisher(name='Apress', address='2855 Telegraph Avenue', ... city='Berkeley', state_province='CA', country='U.S.A.', ... website='http://www.apress.com/') >>> p1.save()
2、查询
>>> Publisher.objects.all() [<Publisher: Apress>, <Publisher: O'Reilly>]
获取单个对象:
>>> Publisher.objects.get(name="Apress") <Publisher: Apress>如果结果是多个对象或者没有返回结果则会抛出异常
3、条件
筛选:
>>> Publisher.objects.filter(name='Apress') [<Publisher: Apress>]>>> Publisher.objects.filter(name__contains="press") [<Publisher: Apress>]__contains部分会被Django翻译成LIKE语句
排序:
>>> Publisher.objects.order_by("name") [<Publisher: Apress>, <Publisher: O'Reilly>]
相当于 order by name asc
>>> Publisher.objects.order_by("-name")加个负号相当于 order by name desc
限制返回数据:
>>> Publisher.objects.order_by('name')[0] <Publisher: Apress>相当于 limit 1
>>> Publisher.objects.order_by('name')[0:2]相当于 OFFSET 0 LIMIT 2
4、更新
>>> Publisher.objects.filter(id=52).update(name='Apress Publishing')>>> p = Publisher.objects.get(name='Apress') #先查询 >>> p.name = 'Apress Publishing' #更新 >>> p.save() #保存5、删除
>>> p = Publisher.objects.get(name="O'Reilly") >>> p.delete()>>> Publisher.objects.filter(country='USA').delete()
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