日期:2014-05-16  浏览次数:20512 次

在oracle中处理日期大全

在oracle中处理日期大全

?? TO_DATE格式??
Day:??
dd number 12??
dy abbreviated fri??
day spelled out friday??
ddspth spelled out, ordinal twelfth??
Month:??
mm number 03??
mon abbreviated mar??
month spelled out march??
Year:??
yy two digits 98??
yyyy four digits 1998??

24小时格式下时间范围为: 0:00:00 - 23:59:59....??
12小时格式下时间范围为: 1:00:00 - 12:59:59 ....??
1.??
日期和字符转换函数用法(to_date,to_char)??

2.??
select to_char( to_date(222,'J'),'Jsp') from dual??

显示Two Hundred Twenty-Two??

3.??
求某天是星期几??
select to_char(to_date('2002-08-26','yyyy-mm-dd'),'day') from dual;??
星期一??
select to_char(to_date('2002-08-26','yyyy-mm-dd'),'day','NLS_DATE_LANGUAGE = American') from dual;??
monday??
设置日期语言??
ALTER SESSION SET NLS_DATE_LANGUAGE='AMERICAN';??
也可以这样??
TO_DATE ('2002-08-26', 'YYYY-mm-dd', 'NLS_DATE_LANGUAGE = American')??

4.??
两个日期间的天数??
select floor(sysdate - to_date('20020405','yyyymmdd')) from dual;??

5. 时间为null的用法??
select id, active_date from table1??
UNION??
select 1, TO_DATE(null) from dual;??

注意要用TO_DATE(null)??

6.??
a_date between to_date('20011201','yyyymmdd') and to_date('20011231','yyyymmdd')??
那么12月31号中午12点之后和12月1号的12点之前是不包含在这个范围之内的。??
所以,当时间需要精确的时候,觉得to_char还是必要的??
7. 日期格式冲突问题??
输入的格式要看你安装的ORACLE字符集的类型, 比如: US7ASCII, date格式的类型就是: '01-Jan-01'??
alter system set NLS_DATE_LANGUAGE = American??
alter session set NLS_DATE_LANGUAGE = American??
或者在to_date中写??
select to_char(to_date('2002-08-26','yyyy-mm-dd'),'day','NLS_DATE_LANGUAGE = American') from dual;??
注意我这只是举了NLS_DATE_LANGUAGE,当然还有很多,??
可查看??
select * from nls_session_parameters??
select * from V$NLS_PARAMETERS??

8.??
select count(*)??
from ( select rownum-1 rnum??
from all_objects??
where rownum <= to_date('2002-02-28','yyyy-mm-dd') - to_date('2002-??
02-01','yyyy-mm-dd')+1??
)??
where to_char( to_date('2002-02-01','yyyy-mm-dd')+rnum-1, 'D' )??
not??
in ( '1', '7' )??

查找2002-02-28至2002-02-01间除星期一和七的天数??
在前后分别调用DBMS_UTILITY.GET_TIME, 让后将结果相减(得到的是1/100秒, 而不是毫秒).??

9.??
select months_between(to_date('01-31-1999','MM-DD-YYYY'),??
to_date('12-31-1998','MM-DD-YYYY')) "MONTHS" FROM DUAL;??
1??

select months_between(to_date('02-01-1999','MM-DD-YYYY'),??
to_date('12-31-1998','MM-DD-YYYY')) "MONTHS" FROM DUAL;??

1.03225806451613??
10. Next_day的用法??
Next_day(date, day)??

Monday-Sunday, for format code DAY??
Mon-Sun, for format code DY??
1-7, for format code D??

11??
select to_char(sysdate,'hh:mi:ss') TIME from all_objects??
注意:第一条记录的TIME 与最后一行是一样的??
可以建立一个函数来处理这个问题??
create or replace function sys_date return date is??
begin??
return sysdate;??
end;??

select to_char(sys_date,'hh:mi:ss') from all_objects;??
12.??
获得小时数??

SELECT EXTRACT(HOUR FROM TIMESTAMP '2001-02-16 2:38:40') from offer??
SQL> select sysdate ,to_char(sysdate,'hh') from dual;??

SYSDATE TO_CHAR(SYSDATE,'HH')??
-------------------- ---------------------??
2003-10-13 19:35:21 07??

SQL> select sysdate ,to_char(sysdate,'hh24') from dual;??

SYSDATE TO_CHAR(SYSDATE,'HH24')??
-------------------- -----------------------??
2003-10-13 19:35:21 19??

获取年月日与此类似??
13.??
年月日的处理??
select older_date,??
newer_date,??
years,??
months,??
abs(??
trunc(??
newer_date-??
add_months( older_date,years*12+months )??
)??
) days??
from ( select??
trunc(months_between( newer_date, older_date )/12) YEARS,??
mod(trunc(months_between( newer_date, older_date )),??
12 ) MONTHS,??
newer_date,??
older_date??
from ( select hiredate older_date,??
add_months(hiredate,rownum)+rownum newer_date??
from emp )??
)??

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