日期:2014-05-16 浏览次数:20394 次
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people 2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录 3、查找表中多余的重复记录(多个字段)? 4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录 (二) 如果还查性别也相同大则如下: (三) declare @max integer,@id integer declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1 open cur_rows fetch cur_rows into @id,@max while @@fetch_status=0 begin
?
where peopleId in (select? peopleId? from? people? group? by? peopleId? having? count(peopleId) > 1)
delete from people?
where peopleId? in (select? peopleId? from people? group? by? peopleId?? having? count(peopleId) > 1)
and rowid not in (select min(rowid) from? people? group by peopleId? having count(peopleId )>1)
select * from vitae a
where (a.peopleId,a.seq) in? (select peopleId,seq from vitae group by peopleId,seq? having count(*) > 1)
delete from vitae a
where (a.peopleId,a.seq) in? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From A Group By Name Having Count(*) > 1
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1
方法一