private void textBox1_KeyPress( object sender, KeyPressEventArgs e )
        {
            if ( e.KeyChar == (char) Keys.Enter )
            {
                button1.PerformClick();
            }
        }

        private void textBox2_KeyPress( object sender, KeyPressEventArgs e )
        {
            if ( e.KeyChar == (char) Keys.Enter )
            {
                button2.PerformClick();
            }
        }

        private void button1_Click( object sender, EventArgs e )
        {
            MessageBox.Show( "按钮1" );
        }

        private void button2_Click( object sender, EventArgs e )
        {
            MessageBox.Show( "按钮2" );
        }

------解决方案--------------------
如上面说的一样

------解决方案--------------------
似乎就是这么干

------解决方案--------------------
探讨

C# code
        private void textBox1_KeyPress( object sender, KeyPressEventArgs e )
        {
            if ( e.KeyChar == (char) Keys.Enter )
            {
                button1.PerformClick();
            }
        }

        private void textBox2_KeyPress( object sender, KeyPressEventArgs e )
        {
            if ( e.KeyChar == (char) Keys.Enter )
            {
          …


------解决方案--------------------
在TextBox的KeyDown事件中处理
TextBox1_KeyDown中如果是回车，则调用Button1_Click事件函数
TextBox2_KeyDown中如果是回车，调用Button2_Click事件函数

------解决方案--------------------
用textbox 的KeyPress！四楼很详细了！

------解决方案--------------------
 private void textBox1_KeyDown(object sender, KeyEventArgs e)
       {
           if (e.KeyData == Keys.Enter)
           {
              
                 
                   System.Windows.Forms.SendKeys.Send("{TAB}");
              
           }
       }