请问这个加/解密算法是 已知的什么算法?还是自已写的?

  /// <summary>
  /// 解密/加密
  /// </summary>
  /// <param name="pText">明文</param>
  /// <param name="pPassword">Keys</param>
  /// <param name="pEnCryptTf">true 加密: false 解密</param>
  /// <returns>返回密文</returns>
  private static string EnOrDeCrypt(string pText, string pPassword, bool pEnCryptTf)
  {
  int MulNumber = pEnCryptTf ? 1 : -1;
  int num;
  int num4 = 0;
  int num6 = 0;
  int length = pPassword.Length;
  //num6等于pPassword的每位asscii码相加
  for (num = 0; num < length; num++)
  {
  num6 += pPassword[num];
  }
  //num6 等于 num6 除以 6 的整数
  num6 /= 6;
  int num3 = 0;
  string str = "";
  length = pText.Length;
  for (num = 0; num < length; num++)
  {
  int num5 = pText[num];
  num3++;
  if (num3 == 6)
  {
  num3 = 0;
  }
  switch (num3)
  {
  case 0:
  num4 = num5 - (MulNumber * (num6 - 2));
  break;

  case 1:
  num4 = num5 + (MulNumber * (num6 - 5));
  break;

  case 2:
  num4 = num5 - (MulNumber * (num6 - 4));
  break;

  case 3:
  num4 = num5 + (MulNumber * (num6 - 2));
  break;

  case 4:
  num4 = num5 - (MulNumber * (num6 - 3));
  break;

  case 5:
  num4 = num5 + (MulNumber * (num6 - 5));
  break;
  }
  if (num5 == 0)
  {
  Run.Exception.Throw(null,"EnOrDeCrypt中出现无法处理的字符");
  }
  int num7 = 1;
  if (num4 > 0xffff)//0xffff=65535
  {
  num4 = num7 + ((num4 - 0xffff) - 1);
  }
  if (num4 < num7)
  {
  num4 = 0xffff - ((num7 - num4) - 1);
  }
  str = str + ((char) num4);
  }
  return str;
  }

------解决方案--------------------
肯定是自己写的
------解决方案--------------------
恩。 自己写的了。就是简单的加个ASSCII值。解密一样就可以了。