treeview目录展开问题
我用的是VS2003,我现在碰到的情况是:   左边有个树目录,右边有个表,树目录   
 里有很多级,在右边里选个值,树目录会自动打开所选值的节点。。就像windows的帮   
 助的功能一样。。。   希望有资料的朋友发到资料到我邮箱,问题解决,可以再给分!   
 邮箱:wuxingmaxail@163.com
------解决方案--------------------asp.net 2.0 的 TreeView 即是如此实现   
 TreeView 具有 TreeNode FindNode(string valuePath) 方法   
 TreeNode 具有 Collapse 和 Expand 方法   
 思路既是如此 ...
------解决方案--------------------///  <summary>  
     /// 建树 
     ///  </summary>  
     ///  <param name= "father "> 父号码 </param>  
     protected void treeNode(string father, TreeNode fatherNode) 
     { 
         if (father !=  " ") 
         { 
             DataRow[] rows = dt.Select( "Father= ' " + father +  " ' ",  "CreateDate asc "); 
             if (0 != rows.Length) 
             { 
                 foreach (DataRow row in rows) 
                 { 
                     TreeNode newTreeNode = new TreeNode(); 
                     newTreeNode.Text = row.ItemArray[0].ToString() +  "( " + row.ItemArray[1].ToString() +  ") "; 
                     newTreeNode.Value = row.ItemArray[0].ToString(); 
                     newTreeNode.Expanded = false;                     
                     if (onlyOne) 
                     { 
                         this.tv_Help.Nodes.Add(newTreeNode); 
                         fatherNode = this.tv_Help.Nodes[0];                         
                     } 
                     else 
                     { 
                         fatherNode.ChildNodes.Add(newTreeNode);                        
                     } 
                     DataRow[] rs = dt.Select( "father= ' " + newTreeNode.Value +  " ' "); 
                     if (0 != rs.Length && !onlyOne) 
                     { 
                         treeNode(row.ItemArray[0].ToString(), newTreeNode); 
                     } 
                     if (onlyOne) 
                     { 
                         onlyOne = false; 
                         treeNode(row.ItemArray[0].ToString(), fatherNode); 
                     } 
                 } 
             } 
             else 
             { 
                 return; 
             } 
         } 
         else 
         { 
             TreeNode newTreeNode = new TreeNode(); 
             newTreeNode.Text =  "业务类型 "; 
             newTreeNode.Value =  "HOWIN ";             
             this.tv_Help.Nodes.Add(newTreeNode);           
             fatherNode = this.tv_Help.Nodes[0]; 
             onlyOne = false;             
             treeNode( "HOWIN ",fatherNode);             
         } 
     } 
     public void SetAllNodeText(TreeNodeCollection tnc) 
     { 
         foreach (TreeNode node in tnc) 
         { 
             if (node.ChildNodes.Count == 0) 
             { 
                 node.NavigateUrl =  "javascript:goback( ' " + node.Value +  " '); ";                   
             } 
             if (node.ChildNodes.Count != 0) 
             { 
                 SetAllNodeText(node.ChildNodes); 
             } 
         } 
     }