这个简单程序如何不运行呀
<%@   Page   Language= "C# "   %>    
  <!DOCTYPE   html   PUBLIC    "-//W3C//DTD   XHTML   1.0   Transitional//EN "    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd ">    
  <script   runat= "server ">    
  </script>    
  <html   xmlns= "http://www.w3.org/1999/xhtml "   >  
  <head   runat= "server ">  
              <title> 无标题页 </title>  
  <script   language= "javascript "   type= "text/javascript ">  
 //    <!CDATA[   
 function   Text1_onmouseout()   { 
 if   (Text1.value== " "){ 
 alert( "不能为空 "); 
 Text1.focus(); 
 } 
 }   
 //   ]]>  
  </script>  
  </head>  
  <body>  
              <form   id= "form1 "   runat= "server ">  
              <div>  
                          <input   id= "Text1 "   type= "text "   onmouseout= "return   Text1_onmouseout() "   />  </div>  
              </form>  
  </body>  
  </html>  
------解决方案--------------------//  <!CDATA[   
 function Text1_onmouseout() { 
 if (Text1.value== " "){ 
 alert( "不能为空 "); 
 Text1.focus(); 
 } 
 }   
 // ]]> 这是个什么东西?
------解决方案--------------------建议你写在焦点离开事件  onblur= "return Text1_onmouseout() " 
 然后你的函数也有问题 
 function Text1_onmouseout() { 
 var Text1=window.document.getElementById( 'Text1 '); 
 if (Text1.value== " "){ 
 alert( "不能为空 "); 
 Text1.focus(); 
 return false; 
 } 
 return true; 
 } 
------解决方案--------------------onmouseout= "return Text1_onmouseout() " 
 这里有问题 
 还有最好用w3c的标准写javascript
------解决方案--------------------function Text1_onmouseout() { 
 if (document.getElementById( "Text1 ").value== " "){ 
 alert( "不能为空 "); 
 Text1.focus(); 
 return; 
 } 
 }   
  <input id= "Text1 " type= "text " onblur= "return Text1_onmouseout() " />  </div>