一个触发器问题请大家帮忙修改!很着急
CREATE   TRIGGER   [trig_omsYunDanJian_Insert] 
          ON      [dbo].[omsYunDanJian] 
          AFTER   INSERT 
 AS      
 --声明变量 
 Declare   @m_zhongliang   decimal(7,2) 
 declare   @m_tiji   decimal(15,6)   
 BEGIN 
 	SET   NOCOUNT   ON;    	 
                         @m_zhongliang   =   select    'ZL '=SUM(ZhongLiang) 
                                                 from   omsYunDanJian 
                                                 where   omsYunDanJian.YunDanID=inserted.YunDanID     
                         @m_tiji=   select    'TJ '=SUM(TiJi) 
                            from   omsYunDanJian 
                            where   omsYunDanJian.YunDanID=inserted.YunDanID  	 
                         if(@m_zhongliang   > 0   ||   @m_tiji   > 0)  	 
 	UPDATE   omsYunDan 
                         SET      
                         ZhongLiang   =   @m_zhongliang   ,   
                         TiJi=@m_tiji=     	 
             from   inserted 
             WHERE   omsYunDan.YunDanID   =   inserted.YunDanID     
             SET   NOCOUNT   OFF     
 END   
 请大家帮我修改一下这个触发器!
------解决方案--------------------差不多这样吧   
 CREATE TRIGGER [trig_omsYunDanJian_Insert] 
    ON  [dbo].[omsYunDanJian] 
    AFTER INSERT 
 AS    
 --声明变量 
 Declare @m_zhongliang decimal(7,2) 
 declare @m_tiji decimal(15,6)   
 BEGIN 
 	SET NOCOUNT ON   
 	select @m_zhongliang = SUM(ZhongLiang) as  'ZL ', @m_tiji = SUM(TiJi) as  'TJ ' 
 	from omsYunDanJian 
 	where omsYunDanJian.YunDanID=inserted.YunDanID  	 
 	if(@m_zhongliang > 0 || @m_tiji > 0) 
 		UPDATE omsYunDan 
         		SET  ZhongLiang = @m_zhongliang , TiJi = @m_tiji  
 		from omsYunDan inner join inserted 
     		on omsYunDan.YunDanID = inserted.YunDanID   
 	SET NOCOUNT OFF 
 END
------解决方案--------------------select @m_zhongliang = SUM(ZhongLiang) as  'ZL ', @m_tiji = SUM(TiJi) as  'TJ ' 
 ============================================================================= 
 select 用法有错; 
 SELECT @var1 =  'Generic Name ' 
 SELECT @var1 AS  'Company Name '    
 不能 SELECT @m_zhongliang = SUM(ZhongLiang) AS   'ZL ' 
------解决方案--------------------select @m_zhongliang = SUM(ZhongLiang), @m_tiji = SUM(TiJi)  
 	from omsYunDanJian inner join inserted 
 	on omsYunDanJian.YunDanID=inserted.YunDanID