如何设置label[i]的值?i是程序中生成的
如题。 
 Delphi中Edit是这样的: 
 i   :=   1; 
 TEdit(FindComponent( 'Edit '   +   IntToStr(i)   +    '1 ')).Text   :=    'TEXT '; 
 这样的话   Edit11.Text   的值就是TEXT了。 
 那如果我想在C#中实现当i的值为程序中生成的任意值时,都可以得到   label[i]呢? 
 假设   i   =   1   ,j   =   2   (j也是一程序中生成的值) 
 我想获得   label1   、label2   、label12   、label21   的操作,怎么弄? 
 其它如   textBox、button   也可以实现吗? 
 最好能列出实例! 
------解决方案----------------------------大概像这样   
 private void button1_Click(object sender, EventArgs e) 
         { 
             this.Text = FindControl(this,  "textBox1 ").Text; 
         }           
         private System.Windows.Forms.Control FindControl(System.Windows.Forms.Control control, string strName) 
         { 
             foreach (System.Windows.Forms.Control subControl in control.Controls) 
             { 
                 if (subControl.Name == strName) 
                 { 
                     return subControl; 
                 } 
                 return FindControl(subControl, strName); 
             } 
             return null; 
         } 
------解决方案--------------------for (int i =0; i <GlobalCategoryPanel.Controls.Count;i++)//GlobalCategoryPanel是个Panel控件 
             { 
                 if(GlobalCategoryPanel.Controls[i] is AdvancedPanel)//AdvancedPanel是个自定义控件 
                 { 
                     AdvancedPanel ap=(AdvancedPanel)GlobalCategoryPanel.Controls[i]; 
                     for(int ap_i=0;ap_i <ap.Controls.Count;ap_i++) 
                     { 
                         if(ap.Controls[ap_i] is Panel) 
                         { 
                             Panel ap_panel=(Panel)ap.Controls[ap_i]; 
                             for(int ap_panel_i=0;ap_panel_i <ap_panel.Controls.Count;ap_panel_i++) 
                             { 
                                 if(ap_panel.Controls[ap_panel_i] is RadioButtonList) 
                                 { 
                                     RadioButtonList rbl=(RadioButtonList)ap_panel.Controls[ap_panel_i]; 
                                     al.Add(int.Parse(rbl.SelectedValue)); 
                                 }                                                   
                             } 
                         } 
                     } 
                 } 
             }
------解决方案--------------------TextBox textbox = this.Controls.Find( "TextBox " + i.ToString() +  "1 ", true); 
 if(textbox != null) 
 textbox.Text =  "TEXt ";