图片如何出入数据库(sql server)
如何将图片保存到数据库里然后再取出并将其显示出来?
------解决方案--------------------最好是存放地址,在服务器上。读的时候直接取地址不就OK了吗?
------解决方案--------------------把图片转成文件流。存入数据库就成。
------解决方案--------------------个人感觉还是存在址的好 
 一来直接保存图片太大 
 二来操作也不方便
------解决方案--------------------private void button1_Click(object sender, EventArgs e) 
         { 
             if (this.openFileDialog1.ShowDialog() != DialogResult.OK) 
                 return; 
             string filename = this.openFileDialog1.FileName; 
             ImageFormat iformat = null; 
             switch(filename.Substring(filename.IndexOf( '. ')+1).ToLower()) 
             { 
                 case  "bmp ": 
                     iformat=ImageFormat.Bmp; 
                     break; 
                 case  "gif ": 
                     iformat=ImageFormat.Gif; 
                     break; 
                 case  "jpg ": 
                     iformat=ImageFormat.Jpeg; 
                     break; 
             } 
             MemoryStream ms = new MemoryStream(); 
             Image imgae=Image.FromFile(filename); 
             imgae.Save(ms, iformat); 
             try 
             { 
                 conn.Open();                
                 SqlCommand cmd = new SqlCommand( "sp_InsertPhoto2 ", conn); 
                 cmd.CommandType = CommandType.StoredProcedure; 
                 cmd.Parameters.Add(new SqlParameter( "@name ", SqlDbType.VarChar)); 
                 cmd.Parameters.Add(new SqlParameter( "@image ", SqlDbType.Image)); 
                 cmd.Parameters[0].Value = Path.GetFileNameWithoutExtension(filename); 
                 cmd.Parameters[1].Value = ms.ToArray(); 
                 cmd.ExecuteNonQuery();   
             } 
             finally 
             { 
                 conn.Close(); 
             } 
         } 
         private Image StreamToImage(byte[] b) 
         { 
             MemoryStream ms = new MemoryStream(b); 
             return Image.FromStream(ms); 
         }   
         private void button2_Click(object sender, EventArgs e) 
         { 
             DataSet ds = GetPhotosDataSet(); 
             if (CurrentIndex  < ds.Tables[0].Rows.Count-1) 
                 this.pictureBox1.Image = StreamToImage((byte[])ds.Tables[0].Rows[++CurrentIndex][1]); 
             else 
             { 
                 CurrentIndex = 0; 
                 this.pictureBox1.Image = StreamToImage((byte[])ds.Tables[0].Rows[CurrentIndex][1]); 
             } 
         }