Spring 问题 求解
package junit.test;
import org.junit.BeforeClass;
import org.junit.Test;
import 
org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import cn.itcast.service.PersonService;
public class SpringTest {
	@BeforeClass
	public static void setUpBeforeClass() throws Exception {
	}
	@Test public void instanceSpring(){
		ApplicationContext ctx=new ClassPathXmlApplicationContext("beans.xml");
		PersonService personService=(PersonService)ctx.getBean("personService");
		personService.save();
	}
}  
2012-6-26 10:30:09 org.springframework.context.support.AbstractApplicationContext prepareRefresh
信息: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@1d1acd3: display name [org.springframework.context.support.ClassPathXmlApplicationContext@1d1acd3]; startup date [Tue Jun 26 10:30:09 CST 2012]; root of context hierarchy
2012-6-26 10:30:09 org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions
信息: Loading XML bean definitions from class path resource [beans.xml]
2012-6-26 10:30:10 org.springframework.context.support.AbstractApplicationContext obtainFreshBeanFactory
信息: Bean factory for application context [org.springframework.context.support.ClassPathXmlApplicationContext@1d1acd3]: org.springframework.beans.factory.support.DefaultListableBeanFactory@12d15a9
2012-6-26 10:30:10 org.springframework.beans.factory.support.DefaultListableBeanFactory preInstantiateSingletons
信息: Pre-instantiating singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory@12d15a9: defining beans [personService]; root of factory hierarchy
2012-6-26 10:30:10 org.springframework.beans.factory.support.DefaultSingletonBeanRegistry destroySingletons
信息: Destroying singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory@12d15a9: defining beans [personService]; root of factory hierarchy
------解决方案--------------------
beans.xml  配置的问题 
PersonService personService=(PersonService)ctx.getBean("personService");
能获取到吗?