jacob操作word,替换书签内容的同时书签也被删除了,有办法保留书签或者插入新的书签吗?
modifyDocByBookmark()方法用于查找doc文档中名为LB_0的书签 
 并把该书签中的文本内容替换成新内容 
 请问在替换书签体中的内容时,能否保留LB_0书签,令它不被删除 
 或者是在新插入的文本内容上加上新的书签? 
 import   com.jacob.activeX.ActiveXComponent; 
 import   com.jacob.com.Dispatch; 
 import   com.jacob.com.Variant;   
 public   static   void   modifyDocByBookmark()   { 
 		ActiveXComponent   app   =   new   ActiveXComponent( "Word.Application "); 
 		String   inFile   =    "D:\\ligy\\my   ebooks\\j4office\\testfile\\wordtemplet_src.doc "; 
 		String   bookMarkKey   =    "LB_0 "; 
 		try   { 
 			app.setProperty( "Visible ",   new   Variant(true)); 
 			Dispatch   documents   =   app.getProperty( "Documents ").toDispatch(); 
 			Dispatch   doc   =   Dispatch.call(documents,    "Open ",   inFile).toDispatch();		 
 			Dispatch   activeDocument   =   app.getProperty( "ActiveDocument ").toDispatch(); 
 			Dispatch   bookMarks   =   app.call(activeDocument,    "Bookmarks ").toDispatch(); 
 			boolean   bookMarkExist1   =   Dispatch.call(bookMarks,    "Exists ",bookMarkKey).toBoolean(); 
 			if   (bookMarkExist1   ==   true)   { 
 				System.out.println( "已找到书签 "+bookMarkKey); 
 				Dispatch   rangeItem   =   Dispatch.call(bookMarks,    "Item ",bookMarkKey).toDispatch(); 
 				Dispatch   range   =   Dispatch.call(rangeItem,    "Range ").toDispatch(); 
 				String   bookMarkValue   =   Dispatch.get(range,    "Text ").toString(); 
 				System.out.println( "从书签 "+bookMarkKey+ "中抓取的内容如下: "+bookMarkValue); 
 				bookMarkValue   =    "书签 "+bookMarkKey+ "中的段落内容已经被删除啦,现在你看到的是替换过来的内容哦,嘿嘿! "; 
 				if   (bookMarkValue   !=   null)   { 
 					Dispatch.put(range,    "Text ",   new   Variant(bookMarkValue)); 
 					//Dispatch.put(range, "Bookmarks ", "LB_001 "); 
 				} 
 			}   else   { 
 				System.out.println( "指定的书签不存在 "); 
 			} 
 		         Dispatch.call(doc,    "Save "); 
 		         Dispatch.call(doc,    "Close ",   new   Variant(true)); 
 		         doc   =   null; 
 		         if   (app   !=   null)   { 
 			         Dispatch.call(app,    "Quit "); 
 			         app   =   null; 
 			      } 
 		         documents   =   null; 
 		}   catch   (Exception   e)   { 
 			e.printStackTrace(); 
 		}    
 	}
------解决方案--------------------关注
------解决方案--------------------有人知道吗?谢谢!