JAVABEAN中写数据库查询语句的问题
环境access+tomcat 
 11111111111111111111111111111111111111111111111111 
 11111111111111111111111111111111111111111111111111 
 access中查询语句: 
 *************** 
 select   *   from   products   where   category= 'computer ' 
 或: 
 select   *   from   products   where   category= "computer " 
 ****************************** 
 javabean中语句: 
 *************** 
 ResultSet   rst=stmt.executeQuery( "select   *   from   Products   where   category= ' "+categoryId+ " ' "); 
 22222222222222222222222222222222222222222222222222 
 22222222222222222222222222222222222222222222222222 
 access中查询语句: 
 *************** 
 select   *   from   products   where   name   like    '*1* '; 
 或 
 select   *   from   products   where   name   like    "*1* "; 
 *************************** 
 javabean中语句: 
 *************** 
 ResultSet   rst=stmt.executeQuery( "select   *   from   Products   where   name   like    '% "+nameId+ "% '    ");     
 谁能给我解释下: '% "+nameId+ "% '   这段文字。。。 
 ******************************************************* 
 具体文件如下: 
 ********************* 
 public   class   ProductBean 
 { 
 	private   Connection   con; 
 	//构造方法,获得数据库的连接。 
 	public   ProductBean(){ 
 		this.con=DataBaseConnection.getConnection(); 
 	} 
 	/按照商品的类别查找商品, 
 	public   Collection   getProductByCategory(String   categoryId)throws   Exception 
 	{ 
 		Statement   stmt=con.createStatement(); 
 		ResultSet   rst=stmt.executeQuery( "select   *   from   Products   where   category= ' "+categoryId+ " ' "); 
 		Collection   ret=new   ArrayList(); 
 		while(rst.next()) 
 		{ 
 			Product   temp=new   Product(); 
 			temp.setProductId(rst.getString( "productid ")); 
 			temp.setCategoryId(rst.getString( "category ")); 
 			temp.setName(rst.getString( "name ")); 
 			temp.setDescription(rst.getString( "descn ")); 
 			temp.setProducer(rst.getString( "producer ")); 
 			temp.setPrice(rst.getString( "price "));   
 			ret.add(temp); 
 		} 
 		con.close(); 
 		return   ret; 
 	}   
 //按名称匹配查询。 
 	public   Collection   getProductByName(String   nameId)throws   Exception 
 	{ 
 		Statement   stmt=con.createStatement(); 
 		ResultSet   rst=stmt.executeQuery( "select   *   from   Products   where   name   like    '% "+nameId+ "% '    "); 
 		Collection   ret=new   ArrayList(); 
 		while(rst.next()) 
 		{ 
 			Product   temp=new   Product(); 
 			temp.setProductId(rst.getString( "productid ")); 
 			temp.setCategoryId(rst.getString( "category ")); 
 			temp.setName(rst.getString( "name ")); 
 			temp.setDescription(rst.getString( "descn ")); 
 			temp.setProducer(rst.getString( "producer ")); 
 			temp.setPrice(rst.getString( "price "));   
 			ret.add(temp); 
 		} 
 		con.close(); 
 		return   ret; 
 	} 
 }   
 *************************************************
------解决方案--------------------System.out.println( "select * from Products where n