日期:2014-05-20  浏览次数:20833 次

父类子类问题
Java code

public class Sub extends Super {
    int argA;
    static int argB;
    int argC = 13;
    {
        System.out.println("动态语句块:Sub.argA = " + (argA = 11));
    }
    static{
        System.out.println("静态语句块:Sub.argB = " + (argB = 12));
    }
    Sub(){
        //super();
        System.out.println("构造方法块:Sub.argC = " + argC);
        print();
        print(argB);
        argA = 30;
    }

    void print(int argA) {
        System.out.println("sub.print(args)");
        System.out.println(argA);
    }
    
    void print(){
        System.out.println("sub.print()");
        System.out.println(argA);
        System.out.println(argB);
    }

    public static void main(String[] args) {
        System.out.print(new Sub().argA);
    }
}

class Super {
    protected int argA = 21;
    protected static int argB;
    static{
        argB = 22;
    }
    Super() {
        print();
        print(argA);
        argA = 23;
    }

    void print(int argA) {
        System.out.println("super.print(args)");
        System.out.println(argA);
    }
    
    void print() {
        System.out.println("super.print()");
        System.out.println(argA);
        System.out.println(argB);
    }
}

执行过程是这样的吗?
static int argB;
int argA;
int argC;
static{
System.out.println("静态语句块:Sub.argB = " + (argB = 12));
}
Sub(){
super();
argC = 13;
  System.out.println("动态语句块:Sub.argA = " + (argA = 11));
System.out.println("构造方法块:Sub.argC = " + argC);
print();
  print(argB);
  argA = 30;
}
求解释。

------解决方案--------------------
顺序+覆盖的问题
------解决方案--------------------
Java code
public class Sub extends Super {
    int argA;
    static int argB;
    int argC = 13;
    { //这里应该是在new 一个Sub实例的时候才打印
        System.out.println("动态语句块:Sub.argA = " + (argA = 11));
    }
    static{
        System.out.println("------------Sub()静态数据模块.-----------") ;
        System.out.println("静态语句块:Sub.argB = " + (argB = 12));
    }
    Sub(){
        //super();
        System.out.println("构造方法块:Sub.argC = " + argC);
        print();
        print(argB);
        argA = 30;
    }

    void print(int argA) {
        System.out.println("sub.print(args)");
        System.out.println(argA);
    }
    
    void print(){
        System.out.println("sub.print()");
        System.out.println(argA);
        System.out.println(argB);
    }

    public static void main(String[] args) {
        System.out.print(new Sub().argA);
    }
}

class Super {
    protected int argA = 21;
    protected static int argB;
    static{
        System.out.println("------------Supper()静态数据模块.-----------") ;
        argB = 22;
    }
    Super() {
        System.out.println("------------Supper()构造函数 begin.-----------") ;
        print();
        print(argA);
        argA = 23;
        System.out.println("------------Supper()构造函数 end.-----------") ;
    }

    void print(int argA) {
        System.out.println("super.print(args)");
        System.out.println(argA);
    }
    
    void print() {
        System.out.println("------------Supper().print() begin .-----------") ;
        System.out.println("Supper().argA = " + argA);
        System.out.println("Supper().argA = " + argB);
        System.out.println("------------Supper().print() end .-----------") ;
        
    }
}

------解决方案--------------------
探讨
大家,覆盖问题没什么好谈的吗?为什么执行父类方法,还要被子类给覆盖。