日期:2014-05-20  浏览次数:20614 次

菜鸟问题!!请高手解决!
class SuperClass 
{  
public SuperClass()
{
}
public SuperClass(String s)
{
s=" ";
}
public void doSomething()
{
System.out.println("这是SuperClass输出的!");
}
}
class SubClass1 extends SuperClass
{
public void doSomething()
{
System.out.println("这是SubClass1输出的!");
}
public void doSth1()
{
System.out.println("这是doSth1输出的!");
}
}
class SubClass2 extends SuperClass
{
public void doSomething()
{
System.out.println("这是SubClass2输出的!");
}
public void doSth1()
{
System.out.println("这是doSth2输出的!");
}
}
public class testLayer
{
public static void main(String arge[])
{
SuperClass x = new SuperClass();
  SuperClass y = new SubClass1();
  SuperClass z = new SubClass2();
x.doSomething();
y.doSth1();
  z.doSth2();
}
}
请高手改正!!谢谢!

------解决方案--------------------
Java code
class SuperClass {
    public SuperClass() {
    }

    public SuperClass(String s) {
        s = "   ";
    }

    public void doSomething() {
        System.out.println("这是SuperClass输出的!");
    }

    public void doSth1() {
        // TODO Auto-generated method stub

    }
}

class SubClass1 extends SuperClass {
    public void doSomething() {
        System.out.println("这是SubClass1输出的!");
    }

    public void doSth1() {
        System.out.println("这是doSth1输出的!");
    }
}

class SubClass2 extends SuperClass {
    public void doSomething() {
        System.out.println("这是SubClass2输出的!");
    }

    public void doSth1() {
        System.out.println("这是doSth2输出的!");
    }
}

public class testLayer {
    public static void main(String arge[]) {
        SuperClass x = new SuperClass();
        SuperClass y = new SubClass1();
        SuperClass z = new SubClass2();
        x.doSomething();
        y.doSomething();
        z.doSomething();
        y.doSth1();
        z.doSth1();
    }
}

------解决方案--------------------
Java code
  public static void main(String arge[]) {
    SuperClass x = new SuperClass();
    SuperClass y = new SubClass1()f");
try{
fff b=new fff();
b.method();
}
catch(NoSuchMethodException e){
e.printStackTrace();
}
}
}
class fff{


}

------解决方案--------------------
Java code
SuperClass z = new SubClass2();

------解决方案--------------------
你重写父类的方法,用父类的引用是可以调用的.而且调用的是子类里的方法,父类的方法被屏蔽了.但是父类看不到子类里的方法,所以父类的引用指向子类的对象,也调用不到子类里的方法的.只能子类自己的对象调用自己的方法.

Java code
class SuperClass {
    public SuperClass() {
    }

    public SuperClass(String s) {
        s = "   ";
    }

    public void doSomething() {
        System.out.println("这是SuperClass输出的!");
    }


}

class SubClass1 extends SuperClass {
    public void doSomething() {
        System.out.println("这是SubClass1输出的!");
    }

    public void doSth1() {
        System.out.println("这是doSth1输出的!");
    }
}

class SubClass2 extends SuperClass {
    public void doSomething() {
        System.out.println("这是SubClass2输出的!");
    }

    public void doSth2() {
        System.out.println("这是doSth2输出的!");
    }
}

public class testLayer {
    public static void main(String arge[]) {
        SuperClass x = new SuperClass();
        SuperClass y = new SubClass1();
        SuperClass z = new SubClass2();
        SubClass1 a = new SubClass1();
        SubClass2 b = new SubClass2();
        x.doSomething();
        y.doSomething();//父类的方法被屏蔽了,调用的是子类里的方法
        z.doSomething();//父类的方法被屏蔽了,调用的是子类里的方法
        //y.doSth1();这里是不可见的,所以不能调用
        //z.doSth2();这里是不可见的,所以不能调用
        a.doSth1();
        b.doSth2();
    }
}