如何实现这样的数组
int[][]   values   =   { 
 {1,2,3,4,5}, 
 {1,2,3,5,4}, 
 {1,2,4,3,5}, 
 {1,2,4,5,3}, 
 {1,2,5,3,4}, 
 {1,2,5,4,3}, 
 {1,3,2,4,5}, 
 {1,3,2,5,4}, 
 {1,3,4,2,5}, 
 {1,3,4,5,2}, 
 {1,3,5,2,4}, 
 {1,3,5,4,2}, 
 {1,4,2,3,5}, 
 {1,4,2,5,3}, 
 {1,4,3,2,5}, 
 {1,4,3,5,2}, 
 {1,4,5,2,3}, 
 {1,4,5,3,2}, 
 {1,5,2,3,4}, 
 {1,5,2,4,3}, 
 {1,5,3,2,4}, 
 {1,5,3,4,2}, 
 {1,5,4,2,3}, 
 {1,5,4,3,2}, 
 {2,1,3,4,5}, 
 {2,1,3,5,4}, 
 {2,1,4,3,5}, 
 {2,1,4,5,3}, 
 {2,1,5,3,4}, 
 {2,1,5,4,3}, 
 {2,3,1,4,5}, 
 {2,3,1,5,4}, 
 {2,3,4,1,5}, 
 {2,3,4,5,1}, 
 {2,3,5,1,4}, 
 {2,3,5,4,1}, 
 {2,4,1,3,5}, 
 {2,4,1,5,3}, 
 {2,4,3,1,5},    
 {2,4,3,5,1}, 
 {2,4,5,1,3}, 
 {2,4,5,3,1}, 
 {2,5,1,3,4}, 
 {2,5,1,4,3}, 
 {2,5,3,1,4}, 
 {2,5,3,4,1}, 
 {2,5,4,1,3}, 
 {2,5,4,3,1}, 
 {3,1,2,4,5}, 
 {3,1,2,5,4}, 
 {3,1,4,2,5}, 
 {3,1,4,5,2}, 
 {3,1,5,2,4}, 
 {3,1,5,4,2}, 
 {3,2,1,4,5}, 
 {3,2,1,5,4}, 
 {3,2,4,1,5}, 
 {3,2,4,5,1}, 
 {3,2,5,1,4}, 
 {3,2,5,4,1}, 
 {3,4,1,2,5}, 
 {3,4,1,5,2}, 
 {3,4,2,1,5}, 
 {3,4,2,5,1}, 
 {3,4,5,1,2}, 
 {3,4,5,2,1}, 
 {3,5,1,2,4}, 
 {3,5,1,4,2}, 
 {3,5,2,1,4}, 
 {3,5,2,4,1}, 
 {3,5,4,1,2}, 
 {3,5,4,2,1}, 
 {4,1,2,3,5}, 
 {4,1,2,5,3}, 
 {4,1,3,2,5}, 
 {4,1,3,5,2}, 
 {4,1,5,2,3}, 
 {4,1,5,3,2}, 
 {4,2,1,3,5}, 
 {4,2,1,5,3}, 
 {4,2,3,1,5}, 
 {4,2,3,5,1}, 
 {4,2,5,1,3}, 
 {4,2,5,3,1}, 
 {4,3,1,2,5}, 
 {4,3,1,5,2}, 
 {4,3,2,1,5}, 
 {4,3,2,5,1}, 
 {4,3,5,1,2}, 
 {4,3,5,2,1}, 
 {4,5,1,2,3}, 
 {4,5,1,3,2}, 
 {4,5,2,1,3}, 
 {4,5,2,3,1}, 
 {4,5,3,1,2}, 
 {4,5,3,2,1}, 
 {5,1,2,3,4}, 
 {5,1,2,4,3}, 
 {5,1,3,2,4}, 
 {5,1,3,4,2}, 
 {5,1,4,2,3}, 
 {5,1,4,3,2}, 
 {5,2,1,3,4}, 
 {5,2,1,4,3}, 
 {5,2,3,1,4}, 
 {5,2,3,4,1}, 
 {5,2,4,1,3}, 
 {5,2,4,3,1}, 
 {5,3,1,2,4}, 
 {5,3,1,4,2}, 
 {5,3,2,1,4}, 
 {5,3,2,4,1},    
 {5,3,4,1,2}, 
 {5,3,4,2,1}, 
 {5,4,1,2,3}, 
 {5,4,1,3,2}, 
 {5,4,2,1,3}, 
 {5,4,2,3,1}, 
 {5,4,3,1,2}, 
 {5,4,3,2,1} 
 };   
 我希望能动态生成 
 而不是一个一个的写成...   
 哪位高手试试看?   
 分不高   
 就有20分   
 呵呵
------解决方案--------------------数学里面的排列问题 
 到版上搜排列或者组合....很多答案。   
 可能具有类似功能的java集合包: 
 http://www.jopener.cn/category/collections-libraries/ 
------解决方案--------------------请参考 
 http://blog.csdn.net/wangjichen_1/archive/2006/10/10/1328887.aspx 
 或者用下面的代码   
 Arrange.java   
 import java.math.*; 
 import java.util.*;   
 public class Arrange{   
 	private int[] index;//用于存储需要全排列的数组的下标的成员变量。 
 	private int n;//表示待排数组的元素个数。 
 	private long numLeft;//用于存储剩余排列序列个数的成员变量。 
 	private long total;//用于存储排列序列总数的成员变量。  	 
 	public Arrange(int n){ 
 		this.n=n; 
 		reset();//调用重置 
 	}  	 
 	public void reset(){ 
 		//初始化数组index。 
 		index=new int[n]; 
 		for(int i = 0; i  < index.length; i++){ 
 			index[i] = i; 
 		}  		 
 		//初始化numLeft,开始时numLeft应该为n!. 
 		total=1; 
 		for(int i = n;i> 1;i--){ 
 			total*=i; 
 		} 
 		numLeft=total; 
 	}   
 	//判断是否排序结束 
 	public boolean hasMore(){ 
 		return numLeft >  0; 
 	}   
 	//得到下一个排列序列 
 	public int[] getNext(){   
 		if (numLeft==total){ 
 			numLeft -=1; 
 			return index; 
 		}   
 		int j = index.length - 2;