public class SimilarityUtil {
    private static int min(int one, int two, int three) {
        int min = one;
        if(two < min) {
            min = two;
        }
        if(three < min) {
            min = three;
        }
        return min;
    }
    
    public static int ld(String str1, String str2) {
        int d[][]; //矩阵
        int n = str1.length();
        int m = str2.length();
        int i; //遍历str1的
        int j; //遍历str2的
        char ch1; //str1的
        char ch2; //str2的
        int temp; //记录相同字符,在某个矩阵位置值的增量,不是0就是1
        if(n == 0) {
            return m;
        }
        if(m == 0) {
            return n;
        }
        d = new int[n+1][m+1];
        for(i=0; i<=n; i++){//初始化第一列
            d[i][0] = i;
        }
        for(j=0; j<=m; j++){//初始化第一行
            d[0][j] = j;
        }
        for(i=1; i<=n; i++) { //遍历str1
            ch1 = str1.charAt(i-1);
            //去匹配str2
            for(j=1; j<=m; j++) {
                ch2 = str2.charAt(j-1);
                if(ch1 == ch2) {
                    temp = 0;
                } else {
                    temp = 1;
                }
                //左边+1,上边+1, 左上角+temp取最小
                d[i][j] = min(d[i-1][j]+1, d[i][j-1]+1, d[i-1][j-1]+temp);
            }
        }
        return d[n][m];
    }
    
    public static double sim(String str1, String str2) {
        int ld = ld(str1, str2);
        return 1 - (double) ld / Math.max(str1.length(), str2.length());
    }

    public static void main(String[] args) {
    
        String str1 = "farmerama";
        String str2 = "aaaaerama";
        System.out.println("ld="+ld(str1, str2));
        System.out.println("sim="+sim(str1, str2));
    }
}

------解决方案--------------------
  
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